Update functions.scala

Modified styling

src/main/scala/com/snowflake/snowpark/functions.scala

@@ -3152,7 +3152,8 @@ object functions {
    * <pre>
    * df = session.createDataFrame(Seq(("CR", "{\"id\": 5, \"name\": \"Jose\", \"age\": 29}"))).toDF(Seq("nationality", "json_string"))
    * </pre>
-   * When the result of this function is the only part of the select statement, no changes are needed:
+   * When the result of this function is the only part of 
+   * the select statement, no changes are needed:
    * <pre>
    * df.select(json_tuple(col("json_string"), "id", "name", "age")).show()
    * </pre>
@@ -3215,8 +3216,10 @@ object functions {
   /**
    * This function converts a JSON string to a variant in Snowflake.
    *
-   * In Snowflake the values are converted automatically, however they're converted as variants, meaning that the printSchema function would return different datatypes.
-   * To convert the datatype and it to be printed as the expected datatype, it should be read on the selectExpr function as "json['relative']['age']::integer".
+   * In Snowflake the values are converted automatically, however they're converted as variants, 
+   * meaning that the printSchema function would return different datatypes.
+   * To convert the datatype and it to be printed as the expected datatype, 
+   * it should be read on the selectExpr function as "json['relative']['age']::integer".
    * <pre>
    * val data_for_json = Seq(
    *   (1, "{\"id\": 172319, \"age\": 41, \"relative\": {\"id\": 885471, \"age\": 29}}"),