You are given a 0-indexed m x n
integer matrix grid
. The width of a column is the maximum length of its integers.
- For example, if
grid = [[-10], [3], [12]]
, the width of the only column is3
since-10
is of length3
.
Return an integer array ans
of size n
where ans[i]
is the width of the ith
column.
The length of an integer x
with len
digits is equal to len
if x
is non-negative, and len + 1
otherwise.
Example 1:
Input: grid = [[1],[22],[333]] Output: [3] Explanation: In the 0th column, 333 is of length 3.
Example 2:
Input: grid = [[-15,1,3],[15,7,12],[5,6,-2]] Output: [3,1,2] Explanation: In the 0th column, only -15 is of length 3. In the 1st column, all integers are of length 1. In the 2nd column, both 12 and -2 are of length 2.
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 100
-109 <= grid[r][c] <= 109
Companies: Samsung
Similar Questions:
// OJ: https://leetcode.com/problems/find-the-width-of-columns-of-a-grid
// Author: github.com/lzl124631x
// Time: O(MND)
// Space: O(D) where D is the length of the longest A[i][j]
class Solution {
public:
vector<int> findColumnWidth(vector<vector<int>>& A) {
int M = A.size(), N = A[0].size();
vector<int> ans(N);
for (int j = 0; j < N; ++j) {
for (int i = 0; i < M; ++i) {
ans[j] = max(ans[j], (int)to_string(A[i][j]).size());
}
}
return ans;
}
};