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You are given a 0-indexed m x n integer matrix grid. The width of a column is the maximum length of its integers.

  • For example, if grid = [[-10], [3], [12]], the width of the only column is 3 since -10 is of length 3.

Return an integer array ans of size n where ans[i] is the width of the ith column.

The length of an integer x with len digits is equal to len if x is non-negative, and len + 1 otherwise.

 

Example 1:

Input: grid = [[1],[22],[333]]
Output: [3]
Explanation: In the 0th column, 333 is of length 3.

Example 2:

Input: grid = [[-15,1,3],[15,7,12],[5,6,-2]]
Output: [3,1,2]
Explanation: 
In the 0th column, only -15 is of length 3.
In the 1st column, all integers are of length 1. 
In the 2nd column, both 12 and -2 are of length 2.

 

Constraints:

  • m == grid.length
  • n == grid[i].length
  • 1 <= m, n <= 100
  • -109 <= grid[r][c] <= 109

Companies: Samsung

Related Topics:
Array, Matrix

Similar Questions:

Solution 1.

// OJ: https://leetcode.com/problems/find-the-width-of-columns-of-a-grid
// Author: github.com/lzl124631x
// Time: O(MND)
// Space: O(D) where D is the length of the longest A[i][j]
class Solution {
public:
    vector<int> findColumnWidth(vector<vector<int>>& A) {
        int M = A.size(), N = A[0].size();
        vector<int> ans(N);
        for (int j = 0; j < N; ++j) {
            for (int i = 0; i < M; ++i) {
                ans[j] = max(ans[j], (int)to_string(A[i][j]).size());
            }
        }
        return ans;
    }
};