You are given a non-negative integer array nums
. In one operation, you must:
- Choose a positive integer
x
such thatx
is less than or equal to the smallest non-zero element innums
. - Subtract
x
from every positive element innums
.
Return the minimum number of operations to make every element in nums
equal to 0
.
Example 1:
Input: nums = [1,5,0,3,5] Output: 3 Explanation: In the first operation, choose x = 1. Now, nums = [0,4,0,2,4]. In the second operation, choose x = 2. Now, nums = [0,2,0,0,2]. In the third operation, choose x = 2. Now, nums = [0,0,0,0,0].
Example 2:
Input: nums = [0] Output: 0 Explanation: Each element in nums is already 0 so no operations are needed.
Constraints:
1 <= nums.length <= 100
0 <= nums[i] <= 100
Companies: Amazon
Related Topics:
Array, Hash Table, Greedy, Sorting, Heap (Priority Queue), Simulation
Similar Questions:
// OJ: https://leetcode.com/problems/make-array-zero-by-subtracting-equal-amounts
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int minimumOperations(vector<int>& A) {
int cnt[101] = {}, ans = 0;
for (int n : A) cnt[n]++;
for (int i = 1; i <= 100; ++i) ans += cnt[i] > 0;
return ans;
}
};