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You are given a non-negative integer array nums. In one operation, you must:

  • Choose a positive integer x such that x is less than or equal to the smallest non-zero element in nums.
  • Subtract x from every positive element in nums.

Return the minimum number of operations to make every element in nums equal to 0.

 

Example 1:

Input: nums = [1,5,0,3,5]
Output: 3
Explanation:
In the first operation, choose x = 1. Now, nums = [0,4,0,2,4].
In the second operation, choose x = 2. Now, nums = [0,2,0,0,2].
In the third operation, choose x = 2. Now, nums = [0,0,0,0,0].

Example 2:

Input: nums = [0]
Output: 0
Explanation: Each element in nums is already 0 so no operations are needed.

 

Constraints:

  • 1 <= nums.length <= 100
  • 0 <= nums[i] <= 100

Companies: Amazon

Related Topics:
Array, Hash Table, Greedy, Sorting, Heap (Priority Queue), Simulation

Similar Questions:

Solution 1.

// OJ: https://leetcode.com/problems/make-array-zero-by-subtracting-equal-amounts
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
    int minimumOperations(vector<int>& A) {
        int cnt[101] = {}, ans = 0;
        for (int n : A) cnt[n]++;
        for (int i = 1; i <= 100; ++i) ans += cnt[i] > 0;
        return ans;
    }
};