<line x1="393.5" y1="70" x2="393.5" y2="450" style="stroke:blue;stroke-width:4" />
<!-- left -->
<line x1="107" y1="70" x2="107" y2="450" style="stroke:blue;stroke-width:4" />
<!-- top -->
<line x1="70" y1="107" x2="430" y2="107" style="stroke:blue;stroke-width:4" />
<!-- bottom -->
<line x1="70" y1="393.1" x2="430" y2="393.1" style="stroke:blue;stroke-width:4" />
<text x="72" y="95" fill="orange">A</text>
<text x="399" y="95" fill="orange">B</text>
<text x="72" y="430" fill="orange">C</text>
<text x="399" y="430" fill="orange">D</text>
<text x="240" y="95" fill="orange">P</text>
<!-- <text x="399" y="95" fill="orange">Q</text> -->
<text x="230" y="430" fill="orange">R</text>
<!-- <text x="399" y="430" fill="orange">S</text> -->
</svg>
<div id = "proofstatements" class = "pullleft">
<br/>
<br/>
AB = CD
<br/>
and<br/> AD = BC
<br/>
<span class = "smallertext">
So we need to prove that adjacent sides of ABCD are equal as well.
if we prove that AB = AD and CD = CB then all sides of ABCD are equal
and ABCD will be proved to be rhombus.
AB = AP + PB
AD = AS +
opposite sides of parallelogram ABCD