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\chapter{Topological Group} | ||
\section{Topological Group} | ||
\begin{definition}{Topological Group}{} | ||
A \textbf{topological group} is a group $G$ equipped with a topology $\tau$ such that the group multiplication map | ||
\begin{align*} | ||
\mu:G\times G&\longrightarrow G\\ | ||
(g,h)&\longmapsto gh | ||
\end{align*} | ||
and the inversion map | ||
\begin{align*} | ||
\sigma:G&\longrightarrow G\\ | ||
g&\longmapsto g^{-1} | ||
\end{align*} | ||
are continuous maps. | ||
\end{definition} | ||
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\noindent Topological groups are the group objects in the category $\mathsf{Top}$. | ||
\begin{definition}{Topological Group Category}{} | ||
Topological groups form a category $\mathsf{TopGrp}$, where the morphisms are continuous group homomorphisms. | ||
\end{definition} | ||
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\noindent An isomorphism of topological groups is a group isomorphism that is also a homeomorphism of the underlying topological spaces. | ||
\begin{proposition}{}{} | ||
The category $\mathsf{TopGrp}$ is complete. Limits in $\mathsf{TopGrp}$ commute with | ||
\begin{itemize} | ||
\item forgetful functor $\mathsf{TopGrp}\to\mathsf{Top}$ | ||
\item forgetful functor $\mathsf{TopGrp}\to\mathsf{Grp}$ | ||
\end{itemize} | ||
\end{proposition} | ||
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\begin{prf} | ||
It is enough to prove the existence and commutation for products and equalizers. Let $R_i, i \in I$ be a collection of topological rings. Take the usual product $R=\prod R_i$ with the product topology. Since $R \times R=\prod\left(R_i \times R_i\right)$ as a topological space (because products commutes with products in any category), we see that addition and multiplication on $R$ are continuous. Let $a, b: R \rightarrow R^{\prime}$ be two homomorphisms of topological rings. Then as the equalizer we can simply take the equalizer of $a$ and $b$ as maps of topological spaces, which is the same thing as the equalizer as maps of rings endowed with the induced topology. | ||
\end{prf} | ||
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\begin{proposition}{Subgroups of Topological Group are Topological Groups}{} | ||
Let $G$ be a topological group and $H$ be a subgroup of $G$. Then $H$ is a topological group with the subspace topology induced by $G$. | ||
\end{proposition} | ||
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\begin{prf} | ||
Since $H$ is a subgroup of $G$, the group multiplication map $\mu:G\times G\to G$ restricts to a map $\mu|_{H\times H}:H\times H\to H$. Since the inclusion $i:H\hookrightarrow G$ is continuous, | ||
\[ | ||
\mu|_{H\times H}:H \times H \xrightarrow{i\times i} G\times G\xrightarrow{\mu}\mu(G) \xrightarrow{i'} H | ||
\] | ||
is also continuous. Similarly, the inversion map $\sigma:G\to G$ restricts to a map $\sigma|_H:H\to H$ and $\sigma|_H$ is continuous. Hence $H$ is a topological group. | ||
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\end{prf} | ||
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\begin{proposition}{Translation Invariance}{} | ||
For any $a \in G$, left or right multiplication by $a$ yields a homeomorphism $G \rightarrow G$. | ||
\end{proposition} | ||
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\begin{prf} | ||
Given any $a\in G$, let | ||
\begin{align*} | ||
L_a=\mu(a,\cdot):G&\longrightarrow G\\ | ||
g&\longmapsto ag | ||
\end{align*} | ||
be the left multiplication map and | ||
\begin{align*} | ||
R_a=\mu(\cdot,a):G&\longrightarrow G\\ | ||
g&\longmapsto ga | ||
\end{align*} | ||
be the right multiplication map. Since the group multiplication map $\mu:G\times G\to G$ is continuous, $L_a$ and $R_a$ must be continuous. Note that $L_a^{-1}=L_{a^{-1}}$ and $R_a^{-1}=R_{a^{-1}}$. Then we see $L_a^{-1}$ and $R_a^{-1}$ are also continuous maps. Hence $L_a$ and $R_a$ are homeomorphisms. | ||
\end{prf} | ||
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\begin{corollary}{}{translation_invariance_cor} | ||
Given any $a \in G$ and $S \subseteq G$, let's denote $a S:=\{a s: s \in S\}$ and $S a:=\{s a: s \in S\}$. Then | ||
\begin{itemize} | ||
\item $S$ is open $\iff$ $a S$ is open $\iff$ $a S$ is open. | ||
\item $S$ is closed $\iff$ $a S$ is closed $\iff$ $a S$ is closed. | ||
\end{itemize} | ||
\end{corollary} | ||
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\begin{proposition}{Neighborhood Basis at $1_G$ Determines the Topology of $G$}{} | ||
Given a topological group $G$, if $\mathcal{N}$ is a neighborhood basis of the identity element $1_G$, then for all $x \in X$, | ||
\[ | ||
x \mathcal{N}:=\{x N: N \in \mathcal{N}\} | ||
\] | ||
is a neighborhood basis of $x$ in $G$. In particular, the topology on $G$ is completely determined by any neighborhood basis at the identity element. | ||
\end{proposition} | ||
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\begin{prf} | ||
Let $x \in G$ and $V$ be any neighborhood of $x$. There exists an open set $U$ such that $x\in U\subseteq V$. By \Cref{th:translation_invariance_cor}, $x^{-1} U$ is an open neighborhood of $1_G$. Since $\mathcal{N}$ is a neighborhood basis of $1_G$, there exists $N \in \mathcal{N}$ such that $N \subseteq x^{-1} U$. Then there exists $x N \in x \mathcal{N}$ such that $x N \subseteq U$. Hence $x \mathcal{N}$ is a neighborhood basis of $x$. | ||
\end{prf} | ||
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\begin{definition}{Inverse Limit in $\mathsf{TopGrp}$}{} | ||
Let $\mathsf{I}$ be a \hyperref[th:filtered_category]{filtered} \hyperref[th:thin_category]{thin category} and $F:\mathsf{I}^{\mathrm{op}}\to \mathsf{TopGrp}$ be a functor. Similar to the \hyperref[th:inverse_limit_of_groups]{inverse limit in \textsf{Grp}}, we can unpack the information of $F$ into an inverse system $\left(\left(G_i\right)_{i \in I},\left(f_{i j}\right)_{i \leq j \in I}\right)$. The inverse limit of this inverse system is $\varprojlim F$, also denoted by $\varprojlim_{i\in I}G_i$.\\ | ||
To give a concrete construction of $\varprojlim_{i\in I}G_i$, we can take the inverse limit of the underlying group and endow it with the subspace topology induced by the product topology on $\prod_{i\in I}G_i$. | ||
\end{definition} | ||
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\section{Continuous Topological Group Action} | ||
\begin{definition}{Compact Open Topology}{} | ||
Let $X$ be a topological space and $K$ be a compact subset of $X$. The \textbf{compact open topology} on $\mathrm{Hom}_{\mathsf{Top}}(X,Y)$ is the topology generated by the subbasis | ||
\[ | ||
\mathcal{S}:=\left\{f\in \mathrm{Hom}_{\mathsf{Top}}(X,Y)\midv K\text{ is compact in }X,\;V\text{ is open in }Y,\;f(K)\subseteq V\right\}. | ||
\] | ||
\end{definition} | ||
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\begin{definition}{Group Action on Topological Space by Homeomorphisms}{} | ||
A \textbf{group action} on a topological space $X$ is a group homomorphism $\rho:G\to \mathrm{Aut}_{\mathsf{Top}}(X)$, where $\mathrm{Aut}_{\mathsf{Top}}(X)$ is the group of all homeomorphisms from $X$ to itself. | ||
\end{definition} | ||
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\begin{definition}{Continuous Topological Group Action on Topological Space}{} | ||
A \textbf{continuous topological group action} on a topological space $X$ is a group homomorphism $\rho:G\to \mathrm{Aut}_{\mathsf{Set}}(X)$, where $G$ is a topological group, such that the following map induced by $\rho$ | ||
\begin{align*} | ||
\varrho:G\times X&\longrightarrow X\\ | ||
(g,x)&\longmapsto \rho(g)(x) | ||
\end{align*} | ||
is continuous. In this case, we have $\mathrm{im}\rho \subseteq \mathrm{Aut}_{\mathsf{Top}}(X)$. | ||
\end{definition} | ||
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\begin{prf} | ||
For any $g\in G$, | ||
\begin{align*} | ||
\rho(g): X &\longrightarrow X\\ | ||
x &\longmapsto \varrho(g,x) | ||
\end{align*} | ||
is continuous and has a continuous inverse $\rho(g^{-1})$. Hence $\rho(g)\in \mathrm{Aut}_{\mathsf{Top}}(X)$. | ||
\end{prf} | ||
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From the definition, we see if $varpho:G\times X\to X$ is continuous topological group action on topological space $X$, it is also a group action on $X$ by homeomorphisms. If $G$ is discrete, then the converse holds. | ||
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\begin{proposition}{Discrete Group Acts Continuously on Topological Space $\iff$ Acts by Homeomorphisms}{} | ||
Let $G$ be a group acting on the underlying set of a topological space $X$ through a group homomorphism $\rho:G\to \mathrm{Aut}_{\mathsf{Set}}(X)$. Then the following are equivalent: | ||
\begin{enumerate}[(i)] | ||
\item $G$ equipped with discrete topology acts continuously on $X$ | ||
\item $G$ acts by homeomorphisms on $X$, i.e., | ||
$\mathrm{im}\rho \subseteq \mathrm{Aut}_{\mathsf{Top}}(X)$ | ||
\end{enumerate} | ||
\end{proposition} | ||
\begin{prf} | ||
We only need to prove (ii)$\implies$ (i). For any open set $U\subseteq X$, we have | ||
\begin{align*} | ||
\varrho^{-1}(U)&=\{(g,x)\in G\times X\mid \varrho(g,x)\in U\}\\ | ||
&=\{(g,x)\in G\times X\mid \rho(g)(x)\in U\}\\ | ||
&=\{(g,x)\in G\times X\mid x\in \rho(g)^{-1}(U)\}\\ | ||
&=\bigcup_{g\in G}\left(\left\{g\right\}\times \rho(g)^{-1}(U) \right) | ||
\end{align*} | ||
Since $\rho(g)$ is a homeomorphism, $\rho(g)^{-1}(U)$ is open for any open set $U$. Since $G$ is discrete, each $\left\{g\right\}\times \rho(g)^{-1}(U)$ is open in $G\times X$. Hence $\varrho^{-1}(U)$ as a union of open sets is open in $G\times X$, which implies $\varrho$ is continuous. | ||
\end{prf} | ||
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\begin{definition}{Orbit Space}{} | ||
Let $G$ be a group acting on a topological space $X$. The \textbf{orbit space} of $X$ under the action of $G$ is the quotient space $G\backslash X $ obtained by identifying all points in $X$ that are in the same orbit. $G\backslash X $ is equipped with the quotient topology: a subset $U\subseteq G\backslash X $ is open if and only if $\pi^{-1}(U)$ is open in $X$, where $\pi:X\to G\backslash X$ is the quotient map. | ||
\end{definition} | ||
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\begin{proposition}{}{} | ||
For any continuous action of a topological group $G$ on a topological space $E$, the quotient map $p: E \rightarrow G\backslash E$ is an open map. | ||
\end{proposition} | ||
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\begin{prf} | ||
For any $g \in G$ and any subset $U \subseteq M$, we define a set $g \cdot U \subseteq M$ by | ||
$$ | ||
g \cdot U=\{g \cdot x: x \in U\} . | ||
$$ | ||
If $U \subseteq M$ is open, then $\pi^{-1}(\pi(U))$ is equal to the union of all sets of the form $g \cdot U$ as $g$ ranges over $G$. Since $p \mapsto g \cdot p$ is a homeomorphism, each such set is open, and therefore $\pi^{-1}(\pi(U))$ is open in $M$. Becaues $\pi$ is a quotient map, this implies that $\pi(U)$ is open in $G\backslash M$, and therefore $\pi$ is an open map. | ||
\end{prf} | ||
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\section{Topological Ring} | ||
\begin{definition}{Topological Ring}{} | ||
A \textbf{topological ring} is a ring $R$ equipped with a topology $\tau$ such that the ring addition map | ||
\begin{align*} | ||
+:R\times R&\longrightarrow R\\ | ||
(a,b)&\longmapsto a+b | ||
\end{align*} | ||
the ring multiplication map | ||
\begin{align*} | ||
\cdot:R\times R&\longrightarrow R\\ | ||
(a,b)&\longmapsto a\cdot b | ||
\end{align*} | ||
and the addition inverse map | ||
\begin{align*} | ||
-:R&\longrightarrow R\\ | ||
a&\longmapsto -a | ||
\end{align*} | ||
are continuous maps. | ||
\end{definition} | ||
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