fix: fix path of the file output from the tool

[k-takeuchi220]

• Do only one thing
• Non breaking API changes
• Tested WIP

What did this pull request do?

Due to the following problems, we have changed the output destination of the files.

Problem 1

When specified as follows, the model file is created in ./src/model:
What I expect is for the model file to be created in ./src/domain/model:

gentool -dsn "" -onlyModel -outPath "src/domain"

Problem 2

Using the modelPkgName option also exhibits strange behavior when specifying a string containing a path separator.
In this case, since outPath is not specified, it is expected that the model files would be generated in dto/model/src/domain, but in reality, they are created in ./src/domain.

gentool -dsn "" -onlyModel -modelPkgName "src/domain"

Current behavior

If modelPkgName does not contain a path separator, output the model files to outPath + modelPkgName.
If modelPkgName contains a path separator, output the model files to the path specified in modelPkgName.

Problem 3

The outputPath specifies the location of the query folder, and the location of the model file is determined accordingly.
However, from a naming perspective, I think this is confusing and not a suitable behavior.

User Case Description

Behavior after modification

I have added an option called queryPkgName. The destination for generating query files will be outPath + queryPkgName. This applies similarly if queryPkgName contains a path separator.

Likewise, the destination for generating model files will be outPath + modelPkgName. This also applies similarly if modelPkgName contains a path separator.

There is no change in default behavior if no output destination is specified. However, it is important to note that if the outPath option and modelPkgName option are specified and used, the generated results may differ.