feat: use ast-based helpers

[ojeytonwilliams]

Checklist:

• I have read and followed the contribution guidelines.
• I have read and followed the how to open a pull request guide.
• My pull request targets the main branch of freeCodeCamp.
• I have tested these changes either locally on my machine, or GitPod.

This makes use of the new tools for evaluating python code, recently added to https://github.com/freeCodeCamp/curriculum-helpers/ and documented
here

I added a sample curriculum test and there are a bunch of tests of the code itself in the curriculum-helpers. They demonstrate multiple ways to use the library.

[ghost]

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[ojeytonwilliams]

I'm not sure why the Italian and Portuguese are failing here, but not in main. The next challenge (step 37) is missing, but that's true for main, too.

I'll dig into that, but otherwise this should be good to go.

[ShaunSHamilton]

Makes sense, but I thought we wanted to move away from using the fake filesystem because it was messing up tests?

[ojeytonwilliams]

Makes sense, but I thought we wanted to move away from using the fake filesystem because it was messing up tests?

No, not really. It's more that we want to avoid nesting a test runner inside our own test runner. We didn't need to do it and it make it hard to debug failing tests.

As for why I used it here: it seemed easier than figuring out how to escape the code string. If there's a nice way to do that, we can drop the FS stuff.

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[ojeytonwilliams]

Ooof, more regex issues. @ShaunSHamilton if you've got any ideas, let me know, otherwise I'll have another go.

[ShaunSHamilton]

@ojeytonwilliams Why is just the i18n stuff failing?

[ojeytonwilliams]

@ojeytonwilliams Why is just the i18n stuff failing?

I've not dug into it, but they must have different solutions since they're not syncing properly at the moment.

Assuming that's correct, those solutions are confusing the regex, but are probably valid python.

[ShaunSHamilton]

This should fix the failing test: freeCodeCamp/curriculum-helpers#148

Here is /english/:

        else:
            
            key_char = key[key_index % len(key)]

Here is /portugues/:

        else:

            key_char = key[key_index % len(key)]