Don't use transparent proxying for clients on the listener itself #374
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It's not possible to bind to the same address and port when the client is the same as the listener because it will already be in use by the incoming connection. Detect this and use a new port on the same address instead.
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It's not possible to bind to the same address and port when the client is the same as the listener because it will already be in use by the incoming connection. Detect this and use a new port on the same address instead.