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Assgn#2 #237

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74 changes: 66 additions & 8 deletions Assignment 2-2020.Rmd
Original file line number Diff line number Diff line change
Expand Up @@ -96,13 +96,30 @@ pairs(D5)
#round() rounds numbers to whole number values
#sample() draws a random samples from the groups vector according to a uniform distribution

score <- rnorm(100, 75, 15)
hist(score,breaks = 30)
S1 <- data.frame(score)

library(dplyr)
S1 <- filter(S1, score <= 100)
hist(S1$score)

S2 <- data.frame(rep(100,100-NROW(S1)))
names(S2) <- "score"
S3 <- bind_rows(S1,S2)

interest <- c("sport", "music", "nature", "literature")

S3$interest <- sample(interest, 100, replace = TRUE)

S3$stid <- seq(1,100,1)

```

2. Using base R commands, draw a histogram of the scores. Change the breaks in your histogram until you think they best represent your data.

```{r}

hist(S3$score, breaks = 9)
```


Expand All @@ -111,19 +128,22 @@ pairs(D5)
```{r}
#cut() divides the range of scores into intervals and codes the values in scores according to which interval they fall. We use a vector called `letters` as the labels, `letters` is a vector made up of the letters of the alphabet.

label <- letters[1:9]
S3$breaks <- cut(S3$score, breaks = 9, labels = label)

```

4. Now using the colorbrewer package (RColorBrewer; http://colorbrewer2.org/#type=sequential&scheme=BuGn&n=3) design a pallette and assign it to the groups in your data on the histogram.

```{r}
library(RColorBrewer)
#Let's look at the available palettes in RColorBrewer

display.brewer.all()
#The top section of palettes are sequential, the middle section are qualitative, and the lower section are diverging.
#Make RColorBrewer palette available to R and assign to your bins

S3$colors <- brewer.pal(10, "Set3")
#Use named palette in histogram

hist(S3$score, col = S3$colors)
```


Expand All @@ -132,34 +152,39 @@ library(RColorBrewer)
```{r}
#Make a vector of the colors from RColorBrewer

interest.col <- brewer.pal(4,"Dark2")

boxplot(score ~ interest, S3, col = interest.col)
```


6. Now simulate a new variable that describes the number of logins that students made to the educational game. They should vary from 1-25.

```{r}

S3$login <- sample(1:25, 100, replace = TRUE)
```

7. Plot the relationships between logins and scores. Give the plot a title and color the dots according to interest group.

```{r}
plot(S3$login, S3$score, col = S3$colors, main = "Students Logins vs. Scores")


S3$col1 <- ifelse(S3$interest == "sport", "Red", "Green")
```


8. R contains several inbuilt data sets, one of these in called AirPassengers. Plot a line graph of the the airline passengers over time using this data set.

```{r}

AP <- data.frame(AirPassengers)
plot(AirPassengers)
```


9. Using another inbuilt data set, iris, plot the relationships between all of the variables in the data set. Which of these relationships is it appropraiet to run a correlation on?

```{r}

plot(iris)
```

# Part III - Analyzing Swirl
Expand All @@ -172,6 +197,10 @@ In this repository you will find data describing Swirl activity from the class s

1. Insert a new code block
2. Create a data frame from the `swirl-data.csv` file called `DF1`
```{r}
DF1 <- read.csv("swirl-data.csv", TRUE)

```

The variables are:

Expand All @@ -185,18 +214,47 @@ The variables are:
`hash` - anonymyzed student ID

3. Create a new data frame that only includes the variables `hash`, `lesson_name` and `attempt` called `DF2`
```{r}

DF2 <- data.frame(DF1[,c("hash","lesson_name","attempt")])

```

4. Use the `group_by` function to create a data frame that sums all the attempts for each `hash` by each `lesson_name` called `DF3`
```{r}

DF3 <- DF2 %>% group_by(hash,lesson_name) %>% summarise(attempt_sum = sum(attempt))

```

5. On a scrap piece of paper draw what you think `DF3` would look like if all the lesson names were column names

6. Convert `DF3` to this format
```{r}

spread(DF3, lesson_name, attempt_sum)

```

7. Create a new data frame from `DF1` called `DF4` that only includes the variables `hash`, `lesson_name` and `correct`
```{r}

DF4 <- data_frame(DF1 [,c ("hash", "lesson_name", "correct")])

```

8. Convert the `correct` variable so that `TRUE` is coded as the **number** `1` and `FALSE` is coded as `0`
```{r}

DF4$correct <- ifelse(DF4$correct == TRUE, 1, 0)

```

9. Create a new data frame called `DF5` that provides a mean score for each student on each course
```{r}

DF5 <- DF4 %>% group_by(hash, lesson_name) %>% summarise(mean_correct = mean(correct))
```

10. **Extra credit** Convert the `datetime` variable into month-day-year format and create a new data frame (`DF6`) that shows the average correct for each day

Expand Down
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