sched/debug: Fix the alignment of the show-state debug output

Current sysrq(t) output task fields name are not aligned with
actual task fields value, e.g.:

	kernel: sysrq: Show State
	kernel:  task                        PC stack   pid father
	kernel: systemd         S12456     1      0 0x00000000
	kernel: Call Trace:
	kernel: ? __schedule+0x240/0x740

To make it more readable, print fields name together with task fields
value in the same line, with fixed width:

	kernel: sysrq: Show State
	kernel: task:systemd         state:S stack:12920 pid:    1 ppid:     0 flags:0x00000000
	kernel: Call Trace:
	kernel: __schedule+0x282/0x620

Signed-off-by: Libing Zhou <[email protected]>
Signed-off-by: Ingo Molnar <[email protected]>
Link: https://lore.kernel.org/r/[email protected]

kernel/sched/core.c

@@ -6387,10 +6387,10 @@ void sched_show_task(struct task_struct *p)
 	if (!try_get_task_stack(p))
 		return;
 
-	printk(KERN_INFO "%-15.15s %c", p->comm, task_state_to_char(p));
+	pr_info("task:%-15.15s state:%c", p->comm, task_state_to_char(p));
 
 	if (p->state == TASK_RUNNING)
-		printk(KERN_CONT "  running task    ");
+		pr_cont("  running task    ");
 #ifdef CONFIG_DEBUG_STACK_USAGE
 	free = stack_not_used(p);
 #endif
@@ -6399,8 +6399,8 @@ void sched_show_task(struct task_struct *p)
 	if (pid_alive(p))
 		ppid = task_pid_nr(rcu_dereference(p->real_parent));
 	rcu_read_unlock();
-	printk(KERN_CONT "%5lu %5d %6d 0x%08lx\n", free,
-		task_pid_nr(p), ppid,
+	pr_cont(" stack:%5lu pid:%5d ppid:%6d flags:0x%08lx\n",
+		free, task_pid_nr(p), ppid,
 		(unsigned long)task_thread_info(p)->flags);
 
 	print_worker_info(KERN_INFO, p);
@@ -6435,13 +6435,6 @@ void show_state_filter(unsigned long state_filter)
 {
 	struct task_struct *g, *p;
 
-#if BITS_PER_LONG == 32
-	printk(KERN_INFO
-		"  task                PC stack   pid father\n");
-#else
-	printk(KERN_INFO
-		"  task                        PC stack   pid father\n");
-#endif
 	rcu_read_lock();
 	for_each_process_thread(g, p) {
 		/*