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#include <functional> | ||
#include <vector> | ||
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using namespace std; | ||
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class Solution { | ||
public: | ||
/** | ||
* @brief LC weekly: Bitwise ops | ||
* Bitwise OR(|) and Shifts(>>): fills all bits to the right of | ||
* the highest set bit with ones. | ||
* @param n | ||
* @return int | ||
*/ | ||
int smallestNumber(int n) { | ||
int num = n; | ||
num |= num >> 1; | ||
num |= num >> 2; | ||
num |= num >> 4; | ||
num |= num >> 8; | ||
num |= num >> 16; | ||
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return num; | ||
} | ||
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/** | ||
* @brief LC51: NQueen | ||
* Backtrack | ||
* | ||
* @param n | ||
* @return vector<vector<string>> | ||
*/ | ||
vector<vector<string>> solveNQueens(int n) { | ||
vector<vector<string>> ans; | ||
vector<int> col(n), on_path(n), diag1(n * 2 - 1), diag2(n * 2 - 1); | ||
function<void(int)> dfs = [&](int r) { | ||
// traverse the last row, end | ||
if (r == n) { | ||
vector<string> board(n); | ||
for (int i = 0; i < n; i++) { | ||
board[i] = string(col[i], '.') + 'Q' + string(n - 1 - col[i], '.'); | ||
} | ||
ans.emplace_back(board); | ||
return; | ||
} | ||
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// just traverse every row & col | ||
for (int c = 0; c < n; c++) { | ||
int rc = r - c + n - 1; | ||
if (!on_path[c] && !diag1[r + c] && !diag2[rc]) { | ||
col[r] = c; | ||
// place at pos | ||
on_path[c] = diag1[r + c] = diag2[rc] = true; | ||
// go to next row w/ backtrack | ||
dfs(r + 1); | ||
// recover by undo | ||
on_path[c] = diag1[r + c] = diag2[rc] = false; | ||
} | ||
} | ||
}; | ||
// from first row: row 0 | ||
dfs(0); | ||
return ans; | ||
} | ||
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/** | ||
* @brief LC1564: Greedy Algo: basic version | ||
* but resize the warehouse vector | ||
* Time: O(NlogN), Space: O(1) | ||
* | ||
* @param boxes | ||
* @param warehouse | ||
* @return int | ||
*/ | ||
int maxBoxesInWarehouse(vector<int>& boxes, vector<int>& warehouse) { | ||
// preprocess warehouse height | ||
for (int i = 1; i < warehouse.size(); i++) { | ||
warehouse[i] = min(warehouse[i - 1], warehouse[i]); | ||
} | ||
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sort(boxes.begin(), boxes.end()); | ||
int ans = 0; | ||
for (int i = warehouse.size() - 1; i >= 0; i--) { | ||
if (ans < boxes.size() && boxes[ans] <= warehouse[i]) { | ||
ans++; | ||
} } | ||
return ans; | ||
} | ||
/** | ||
* @brief Refined version of Greedy Algo | ||
* Time: O(NlogN + m), Space: O(1) | ||
* | ||
* @param boxes | ||
* @param warehouse | ||
* @return int | ||
*/ | ||
int maxBoxesInWarehouse2(vector<int>& boxes, vector<int>& warehouse) { | ||
int i = boxes.size() - 1; | ||
int ans = 0; | ||
sort(boxes.begin(), boxes.end()); | ||
for (int room : warehouse) { | ||
// drop boxes not fit | ||
while (i >= 0 && boxes[i] > room) { | ||
i--; | ||
} | ||
if (i == -1) { | ||
return ans; | ||
} | ||
ans++; | ||
i--; | ||
} | ||
return ans; | ||
} | ||
}; |