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Remove .*? from parser #73730

Remove .*? from parser

Remove .*? from parser #73730

Workflow file for this run

#
# Licensed to the Apache Software Foundation (ASF) under one
# or more contributor license agreements. See the NOTICE file
# distributed with this work for additional information
# regarding copyright ownership. The ASF licenses this file
# to you under the Apache License, Version 2.0 (the
# "License"); you may not use this file except in compliance
# with the License. You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing,
# software distributed under the License is distributed on an
# "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
# KIND, either express or implied. See the License for the
# specific language governing permissions and limitations
# under the License.
#
# Intentionally has a general name.
# because the test status check created in GitHub Actions
# currently randomly picks any associated workflow.
# So, the name was changed to make sense in that context too.
# See also https://github.community/t/specify-check-suite-when-creating-a-checkrun/118380/10
name: "On pull requests"
on: pull_request_target
jobs:
label:
name: Label pull requests
runs-on: ubuntu-latest
permissions:
contents: read
pull-requests: write
steps:
- uses: actions/labeler@v5
with:
repo-token: "${{ secrets.GITHUB_TOKEN }}"
sync-labels: true