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Tests all passed! Lots of comments for explanation #50

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80 changes: 70 additions & 10 deletions src/main/java/io/zipcoder/StringsAndThings.java
Original file line number Diff line number Diff line change
Expand Up @@ -14,10 +14,23 @@ public class StringsAndThings {
* countYZ("day fez"); // Should return 2
* countYZ("day fyyyz"); // Should return 2
*/
public Integer countYZ(String input){
return null;
public Integer countYZ(String input) {
int count = 0; //counts the number of times the word ends in a 'y' or 'z'
String[] numberOfWords = input.split(" "); // this splits where there is a space
for (String word : numberOfWords) {
int charactersInWord = word.length(); //this is checking the length of characters in a word
char lastChar = word.charAt(charactersInWord - 1); // we are looking for last character, because we count starting
// at zero, we have to subtract 1 for it to give us the
// correct last character
if (lastChar == 'y' || lastChar == 'z') { //this is saying if the last character is either y or z then it will
// return our desired return
count++;
}
}
return count;
}


/**
* Given two strings, base and remove, return a version of the base string where all instances of the remove string have
* been removed (not case sensitive). You may assume that the remove string is length 1 or more.
Expand All @@ -27,10 +40,15 @@ public Integer countYZ(String input){
* removeString("Hello there", "e") // Should return "Hllo thr"
* removeString("Hello there", "x") // Should return "Hello there"
*/
public String removeString(String base, String remove){
return null;
public String removeString(String base, String remove) {

return base.replace(remove, ""); //remove the characters that were passed through 'remove'
// because it replaces the characters with "" which is an empty string
}




/**
* Given a string, return true if the number of appearances of "is" anywhere in the string is equal
* to the number of appearances of "not" anywhere in the string (case sensitive)
Expand All @@ -39,30 +57,72 @@ public String removeString(String base, String remove){
* containsEqualNumberOfIsAndNot("This is notnot") // Should return true
* containsEqualNumberOfIsAndNot("noisxxnotyynotxisi") // Should return true
*/


public Boolean containsEqualNumberOfIsAndNot(String input){
return null;
int is = 0;
int not = 0;

for (int i =0; i <= input.length() - 3; i++) { // this is initiating at the beginning and running until 3 less than
// the length of the String "input"
if (input.startsWith("is", i)) { // IntelliJ recommended that I use the .startsWith instead of a substring.
// This allows it to check for "is"
is++; // This is allowing it to go to the next "is"
} else if (input.startsWith("not", i)) { // Similar to line 65 except I have "else if" because it is
// saying if it isn't "is", then look for "not"
not++; // Continues to look for other "not"s
}
}

return is == not; // Finally we compare "is" and "not", this will check to see
// if the appearances are equal
}



/**
* We'll say that a lowercase 'g' in a string is "happy" if there is another 'g' immediately to its left or right.
* Return true if all the g's in the given string are happy.
* example : gHappy("xxggxx") // Should return true
* gHappy("xxgxx") // Should return false
* gHappy("xxggyygxx") // Should return false
*/
public Boolean gIsHappy(String input){
return null;
// g must be lowercase
// g is only happy when directly next to another g
// all g's in the string must be happy for it to return true
// probably need to use char to detect a specific character, need lowercase to make sure it isn't a Gg or gG scenario
public Boolean gIsHappy(String input) {
for (int i = 0; i < input.length(); i++) { // the iterates and increments through
if (input.charAt(i) == 'g' && input.charAt(i + 1) == 'g') { // this says that I have a character 'g' and
// if there exists another 'g' next to that g
// then gishappy and will return true.
// (i + 1) just makes sure that the g's are next to each other.
// We didn't need to add an (i-1)
// because the left right part doesn't matter
// because when it finds 'g' it will read from
// left to right, so that first 'g' will always be the left g.
return true;
}
}
return false;
}


/**
* We'll say that a "triple" in a string is a char appearing three times in a row.
* Return the number of triples in the given string. The triples may overlap.
* example : countTriple("abcXXXabc") // Should return 1
* countTriple("xxxabyyyycd") // Should return 3
* countTriple("a") // Should return 0
*/
public Integer countTriple(String input){
return null;
public Integer countTriple(String input){
int count = 0; //counts number of times

for (int i = 0; i <= input.length() - 3; i++) { // the - 3 is there because we are looking for a three character string inside of a larger string
if (input.charAt(i) == input.charAt(i + 1) && input.charAt(i) == input.charAt(i+2))
count++;

}
return count;
}

}
Original file line number Diff line number Diff line change
Expand Up @@ -25,6 +25,7 @@ public void countYZTest1(){
Assert.assertEquals(expected, actual);
}


@Test
public void countYZTest2(){
String input = "day fez";
Expand Down
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