-
Notifications
You must be signed in to change notification settings - Fork 1k
Commit
This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository.
Merge pull request #226 from shikhar9820/master
Create c++ recursive spiral level order tree traversal
- Loading branch information
Showing
1 changed file
with
110 additions
and
0 deletions.
There are no files selected for viewing
110 changes: 110 additions & 0 deletions
110
Recursive Algorithms/DFS/c++ recursive spiral level order tree traversal
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,110 @@ | ||
// Recursive C program for level order traversal of Binary Tree | ||
#include <stdio.h> | ||
#include <stdlib.h> | ||
|
||
/* A binary tree node has data, pointer to left child | ||
and a pointer to right child */ | ||
struct node | ||
{ | ||
int data; | ||
struct node* left, *right; | ||
}; | ||
|
||
/* Function protoypes */ | ||
void printGivenLevel(struct node* root, int level,int counter); | ||
int height(struct node* node); | ||
struct node* newNode(int data); | ||
|
||
/* Function to print level order traversal a tree*/ | ||
void printLevelOrder(struct node* root) | ||
{ | ||
int h = height(root); | ||
int i,j; | ||
for (i=1; i<=h; i++){ | ||
j=i; | ||
printGivenLevel(root,i,j); | ||
} | ||
} | ||
/* Print nodes at a given level */ | ||
void printGivenLevel(struct node* root, int level ,int counter) | ||
{ | ||
if (root == NULL) | ||
return; | ||
if (level == 1) | ||
printf("%d ", root->data); | ||
|
||
else if (level > 1 && (counter%2)!=0) | ||
{ | ||
printGivenLevel(root->right, level-1,counter); | ||
printGivenLevel(root->left, level-1,counter); | ||
} | ||
|
||
else | ||
{ | ||
printGivenLevel(root->left, level-1,counter); | ||
printGivenLevel(root->right, level-1,counter); | ||
} | ||
} | ||
|
||
/* Compute the "height" of a tree -- the number of | ||
nodes along the longest path from the root node | ||
down to the farthest leaf node.*/ | ||
int height(struct node* node) | ||
{ | ||
if (node==NULL) | ||
return 0; | ||
else | ||
{ | ||
/* compute the height of each subtree */ | ||
int lheight = height(node->left); | ||
int rheight = height(node->right); | ||
|
||
/* use the larger one */ | ||
if (lheight > rheight) | ||
return(lheight+1); | ||
else return(rheight+1); | ||
} | ||
} | ||
|
||
/* Helper function that allocates a new node with the | ||
given data and NULL left and right pointers. */ | ||
struct node* newNode(int data) | ||
{ | ||
struct node* node = (struct node*) | ||
malloc(sizeof(struct node)); | ||
node->data = data; | ||
node->left = NULL; | ||
node->right = NULL; | ||
|
||
return(node); | ||
} | ||
|
||
/* Driver program to test above functions*/ | ||
int main() | ||
{ | ||
struct node *root = newNode(1); | ||
root->left = newNode(2); | ||
root->right = newNode(3); | ||
root->right->left = newNode(1); | ||
root->right->right= newNode(9); | ||
root->left->left = newNode(4); | ||
root->left->right = newNode(5); | ||
root->left->left->left = newNode(6); | ||
root->left->right->left = newNode(8); | ||
root->left->right->left->left= newNode(0); | ||
|
||
root->left->right->left->right= newNode(3); | ||
root->left->right->left->right->left= newNode(7); | ||
root->left->right->left->right->right= newNode(5); | ||
root->left->right->left->right->left->left= newNode(9); | ||
root->left->right->left->right->left->right= newNode(6); | ||
|
||
|
||
printf("Level Order traversal of binary tree is \n"); | ||
/*int l; | ||
l=height(root); | ||
printf("%d",l); | ||
*/ | ||
printLevelOrder(root); | ||
return 0; | ||
} |