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(ns sicp.chapter-1.ex-1-16) | ||
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; Exercise 1.16 | ||
; Design a procedure that evolves an iterative exponentiation process | ||
; that uses successive squaring and uses a logarithmic number of steps, as does fast-expt. | ||
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; Hint: | ||
; Using the observation that (b^(n/2))^2 = (b^2)^(n/2), | ||
; keep, along with the exponent n and the base b, an additional state variable a, | ||
; and define the state transformation in such a way that the product ab^n is unchanged from state to state. | ||
; At the beginning of the process a is taken to be 1, and the answer is given by the value of a at the end of the | ||
; process. | ||
; In general, the technique of defining an invariant quantity that remains unchanged from | ||
; state to state is a powerful way to think about the design of iterative algorithms. | ||
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(defn fast-expt | ||
[b n product] | ||
(cond (= n 0) product | ||
(even? n) (fast-expt (* b b) (/ n 2) product) | ||
:else (fast-expt b (- n 1) (* product b)))) | ||
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(defn expt | ||
[b n] | ||
(fast-expt b n 1)) |
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(ns sicp.chapter-1.ex-1-16-test | ||
(:require [clojure.test :refer :all] | ||
[sicp.chapter-1.ex-1-16 :refer [expt]])) | ||
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(deftest expt-test | ||
(is (= 1 (expt 1 2))) | ||
(is (= 3486784401 (expt 3 20)))) |