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ship necessary bioframe code with the library
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# Code copied from bioframe.core.arrops | ||
import numpy as np | ||
import pandas as pd | ||
import warnings | ||
|
||
def arange_multi(starts, stops=None, lengths=None): | ||
""" | ||
Create concatenated ranges of integers for multiple start/length. | ||
Parameters | ||
---------- | ||
starts : numpy.ndarray | ||
Starts for each range | ||
stops : numpy.ndarray | ||
Stops for each range | ||
lengths : numpy.ndarray | ||
Lengths for each range. Either stops or lengths must be provided. | ||
Returns | ||
------- | ||
concat_ranges : numpy.ndarray | ||
Concatenated ranges. | ||
Notes | ||
----- | ||
See the following illustrative example: | ||
starts = np.array([1, 3, 4, 6]) | ||
stops = np.array([1, 5, 7, 6]) | ||
print arange_multi(starts, lengths) | ||
>>> [3 4 4 5 6] | ||
From: https://codereview.stackexchange.com/questions/83018/vectorized-numpy-version-of-arange-with-multiple-start-stop | ||
""" | ||
|
||
if (stops is None) == (lengths is None): | ||
raise ValueError("Either stops or lengths must be provided!") | ||
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if lengths is None: | ||
lengths = stops - starts | ||
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||
if np.isscalar(starts): | ||
starts = np.full(len(stops), starts) | ||
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# Repeat start position index length times and concatenate | ||
cat_start = np.repeat(starts, lengths) | ||
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# Create group counter that resets for each start/length | ||
cat_counter = np.arange(lengths.sum()) - np.repeat( | ||
lengths.cumsum() - lengths, lengths | ||
) | ||
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# Add group counter to group specific starts | ||
cat_range = cat_start + cat_counter | ||
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return cat_range | ||
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def overlap_intervals(starts1, ends1, starts2, ends2, closed=False, sort=False): | ||
""" | ||
Take two sets of intervals and return the indices of pairs of overlapping intervals. | ||
Parameters | ||
---------- | ||
starts1, ends1, starts2, ends2 : numpy.ndarray | ||
Interval coordinates. Warning: if provided as pandas.Series, indices | ||
will be ignored. | ||
closed : bool | ||
If True, then treat intervals as closed and report single-point overlaps. | ||
Returns | ||
------- | ||
overlap_ids : numpy.ndarray | ||
An Nx2 array containing the indices of pairs of overlapping intervals. | ||
The 1st column contains ids from the 1st set, the 2nd column has ids | ||
from the 2nd set. | ||
""" | ||
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for vec in [starts1, ends1, starts2, ends2]: | ||
if isinstance(vec, pd.Series): | ||
warnings.warn( | ||
"One of the inputs is provided as pandas.Series and its index " | ||
"will be ignored.", | ||
SyntaxWarning, | ||
) | ||
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||
starts1 = np.asarray(starts1) | ||
ends1 = np.asarray(ends1) | ||
starts2 = np.asarray(starts2) | ||
ends2 = np.asarray(ends2) | ||
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# Concatenate intervals lists | ||
n1 = len(starts1) | ||
n2 = len(starts2) | ||
ids1 = np.arange(0, n1) | ||
ids2 = np.arange(0, n2) | ||
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# Sort all intervals together | ||
order1 = np.lexsort([ends1, starts1]) | ||
order2 = np.lexsort([ends2, starts2]) | ||
starts1, ends1, ids1 = starts1[order1], ends1[order1], ids1[order1] | ||
starts2, ends2, ids2 = starts2[order2], ends2[order2], ids2[order2] | ||
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# Find interval overlaps | ||
match_2in1_starts = np.searchsorted(starts2, starts1, "left") | ||
match_2in1_ends = np.searchsorted(starts2, ends1, "right" if closed else "left") | ||
# "right" is intentional here to avoid duplication | ||
match_1in2_starts = np.searchsorted(starts1, starts2, "right") | ||
match_1in2_ends = np.searchsorted(starts1, ends2, "right" if closed else "left") | ||
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# Ignore self-overlaps | ||
match_2in1_mask = match_2in1_ends > match_2in1_starts | ||
match_1in2_mask = match_1in2_ends > match_1in2_starts | ||
match_2in1_starts, match_2in1_ends = ( | ||
match_2in1_starts[match_2in1_mask], | ||
match_2in1_ends[match_2in1_mask], | ||
) | ||
match_1in2_starts, match_1in2_ends = ( | ||
match_1in2_starts[match_1in2_mask], | ||
match_1in2_ends[match_1in2_mask], | ||
) | ||
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# Generate IDs of pairs of overlapping intervals | ||
overlap_ids = np.block( | ||
[ | ||
[ | ||
np.repeat(ids1[match_2in1_mask], match_2in1_ends - match_2in1_starts)[ | ||
:, None | ||
], | ||
ids2[arange_multi(match_2in1_starts, match_2in1_ends)][:, None], | ||
], | ||
[ | ||
ids1[arange_multi(match_1in2_starts, match_1in2_ends)][:, None], | ||
np.repeat(ids2[match_1in2_mask], match_1in2_ends - match_1in2_starts)[ | ||
:, None | ||
], | ||
], | ||
] | ||
) | ||
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if sort: | ||
# Sort overlaps according to the 1st | ||
overlap_ids = overlap_ids[np.lexsort([overlap_ids[:, 1], overlap_ids[:, 0]])] | ||
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return overlap_ids |
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numpy | ||
matplotlib | ||
scipy |
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