Fix test. #66
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Fix test. #66
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brzpegasus
reviewed
Aug 24, 2018
| return (...args) => g.apply(null, [f].concat(args)); | ||
| }; | ||
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| wrap(1, (a) => a + 2); |
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Does this specific line play a role in the test failing or passing? Or is it just there to illustrate that g is a function?
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If we don't add this line, then eslint would fail because wrap is an unused variable, not necessarily because of the spread.
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g.apply(g, [f].concat(args))is changing the context of the functionas
gis just being called as such. This change does make it failbecause of the unneeded call.