Curated collection of useful Javascript snippets that you can understand in 30 seconds or less.
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- Snippets are written in ES6, use the Babel transpiler to ensure backwards-compatibility.
- Array difference
- Array intersection
- Array pull (mutates array)
- Array remove
- Array sample
- Array symmetric difference
- Array union
- Array without
- Array zip
- Average of array of numbers
- Chunk array
- Compact
- Count occurrences of a value in array
- Deep flatten array
- Drop elements in array
- Filter out non unique values in an array
- Flatten array up to depth
- Flatten array
- Get max value from array
- Get min value from array
- Group by
- Head of list
- Initial of list
- Initialize array with range
- Initialize array with values
- Last of list
- Median of array of numbers
- Nth element of array
- Pick
- Shuffle array
- Similarity between arrays
- Sum of array of numbers
- Tail of list
- Take every nth element
- Take right
- Take
- Unique values of array
- Bottom visible
- Current URL
- Element is visible in viewport
- Get scroll position
- Redirect to URL
- Scroll to top
- Chain asynchronous functions
- Compose functions
- Curry
- Log function name
- Pipe functions
- Promisify
- Run promises in series
- Sleep
- Collatz algorithm
- Distance between two points
- Divisible by number
- Even or odd number
- Factorial
- Fibonacci array generator
- Greatest common divisor (GCD)
- Hamming distance
- Least common multiple (LCM)
- Percentile
- Powerset
- Random integer in range
- Random number in range
- Round number to n digits
- Standard deviation
- Anagrams of string (with duplicates)
- Capitalize first letter of every word
- Capitalize first letter
- Check for palindrome
- Convert string from camelcase
- Convert string to camelcase
- Reverse a string
- Sort characters in string (alphabetical)
- Truncate a string
- 3 digit hexcode to 6 digit hexcode
- Escape regular expression
- Get native type of value
- Hexcode to RGB
- Is array
- Is boolean
- Is function
- Is number
- Is string
- Is symbol
- Measure time taken by function
- Number to array of digits
- Ordinal suffix of number
- RGB to hexadecimal
- URL parameters
- UUID generator
- Validate email
- Validate number
Create a Set
from b
, then use Array.filter()
on a
to only keep values not contained in b
.
const difference = (a, b) => { const s = new Set(b); return a.filter(x => !s.has(x)); };
// difference([1,2,3], [1,2,4]) -> [3]
Create a Set
from b
, then use Array.filter()
on a
to only keep values contained in b
.
const intersection = (a, b) => { const s = new Set(b); return a.filter(x => s.has(x)); };
// intersection([1,2,3], [4,3,2]) -> [2,3]
Use Array.filter()
and Array.includes()
to pull out the values that are not needed.
Use Array.length = 0
to mutate the passed in array by resetting it's length to zero and Array.push()
to re-populate it with only the pulled values.
const pull = (arr, ...args) => {
let pulled = arr.filter((v, i) => args.includes(v));
arr.length = 0; pulled.forEach(v => arr.push(v));
};
// let myArray = ['a', 'b', 'c', 'a', 'b', 'c'];
// pull(myArray, 'a', 'c');
// console.log(myArray) -> [ 'b', 'b' ]
Use Array.filter()
to find array elements that return truthy values and Array.reduce()
to remove elements using Array.splice()
.
The func
is invoked with three arguments (value, index, array
).
const remove = (arr, func) =>
Array.isArray(arr) ? arr.filter(func).reduce((acc, val) => {
arr.splice(arr.indexOf(val), 1); return acc.concat(val);
}, [])
: [];
// remove([1, 2, 3, 4], n => n % 2 == 0) -> [2, 4]
Use Math.random()
to generate a random number, multiply it with length
and round it of to the nearest whole number using Math.floor()
.
This method also works with strings.
const sample = arr => arr[Math.floor(Math.random() * arr.length)];
// sample([3, 7, 9, 11]) -> 9
Create a Set
from each array, then use Array.filter()
on each of them to only keep values not contained in the other.
const symmetricDifference = (a, b) => {
const sA = new Set(a), sB = new Set(b);
return [...a.filter(x => !sB.has(x)), ...b.filter(x => !sA.has(x))];
}
// symmetricDifference([1,2,3], [1,2,4]) -> [3,4]
Create a Set
with all values of a
and b
and convert to an array.
const union = (a, b) => Array.from(new Set([...a, ...b]));
// union([1,2,3], [4,3,2]) -> [1,2,3,4]
Use Array.filter()
to create an array excluding(using !Array.includes()
) all given values.
const without = (arr, ...args) => arr.filter(v => !args.includes(v));
// without([2, 1, 2, 3], 1, 2) -> [3]
// without([2, 1, 2, 3, 4, 5, 5, 5, 3, 2, 7, 7], 3, 1, 5, 2) -> [ 4, 7, 7 ]
Use Math.max.apply()
to get the longest array in the arguments.
Creates an array with that length as return value and use Array.from()
with a map-function to create an array of grouped elements.
If lengths of the argument-arrays vary, undefined
is used where no value could be found.
const zip = (...arrays) => {
const maxLength = Math.max(...arrays.map(x => x.length));
return Array.from({length: maxLength}).map((_, i) => {
return Array.from({length: arrays.length}, (_, k) => arrays[k][i]);
})
}
//zip(['a', 'b'], [1, 2], [true, false]); -> [['a', 1, true], ['b', 2, false]]
//zip(['a'], [1, 2], [true, false]); -> [['a', 1, true], [undefined, 2, false]]
Use Array.reduce()
to add each value to an accumulator, initialized with a value of 0
, divide by the length
of the array.
const average = arr => arr.reduce((acc, val) => acc + val, 0) / arr.length;
// average([1,2,3]) -> 2
Use Array.from()
to create a new array, that fits the number of chunks that will be produced.
Use Array.slice()
to map each element of the new array to a chunk the length of size
.
If the original array can't be split evenly, the final chunk will contain the remaining elements.
const chunk = (arr, size) =>
Array.from({length: Math.ceil(arr.length / size)}, (v, i) => arr.slice(i * size, i * size + size));
// chunk([1,2,3,4,5], 2) -> [[1,2],[3,4],[5]]
Use Array.filter()
to filter out falsey values (false
, null
, 0
, ""
, undefined
, and NaN
).
const compact = (arr) => arr.filter(Boolean);
// compact([0, 1, false, 2, '', 3, 'a', 'e'*23, NaN, 's', 34]) -> [ 1, 2, 3, 'a', 's', 34 ]
Use Array.reduce()
to increment a counter each time you encounter the specific value inside the array.
const countOccurrences = (arr, value) => arr.reduce((a, v) => v === value ? a + 1 : a + 0, 0);
// countOccurrences([1,1,2,1,2,3], 1) -> 3
Use recursion.
Use Array.concat()
with an empty array ([]
) and the spread operator (...
) to flatten an array.
Recursively flatten each element that is an array.
const deepFlatten = arr => [].concat(...arr.map(v => Array.isArray(v) ? deepFlatten(v) : v));
// deepFlatten([1,[2],[[3],4],5]) -> [1,2,3,4,5]
Loop through the array, using Array.shift()
to drop the first element of the array until the returned value from the function is true
.
Returns the remaining elements.
const dropElements = (arr, func) => {
while (arr.length > 0 && !func(arr[0])) arr.shift();
return arr;
};
// dropElements([1, 2, 3, 4], n => n >= 3) -> [3,4]
Use Array.filter()
for an array containing only the unique values.
const filterNonUnique = arr => arr.filter(i => arr.indexOf(i) === arr.lastIndexOf(i));
// filterNonUnique([1,2,2,3,4,4,5]) -> [1,3,5]
Use recursion, decrementing depth
by 1 for each level of depth.
Use Array.reduce()
and Array.concat()
to merge elements or arrays.
Base case, for depth
equal to 1
stops recursion.
Omit the second element, depth
to flatten only to a depth of 1
(single flatten).
const flattenDepth = (arr, depth = 1) =>
depth != 1 ? arr.reduce((a, v) => a.concat(Array.isArray(v) ? flattenDepth(v, depth - 1) : v), [])
: arr.reduce((a, v) => a.concat(v), []);
// flattenDepth([1,[2],[[[3],4],5]], 2) -> [1,2,[3],4,5]
Use Array.reduce()
to get all elements inside the array and concat()
to flatten them.
const flatten = arr => arr.reduce((a, v) => a.concat(v), []);
// flatten([1,[2],3,4]) -> [1,2,3,4]
Use Math.max()
combined with the spread operator (...
) to get the maximum value in the array.
const arrayMax = arr => Math.max(...arr);
// arrayMax([10, 1, 5]) -> 10
Use Math.min()
combined with the spread operator (...
) to get the minimum value in the array.
const arrayMin = arr => Math.min(...arr);
// arrayMin([10, 1, 5]) -> 1
Use Array.map()
to map the values of an array to a function or property name.
Use Array.reduce()
to create an object, where the keys are produced from the mapped results.
const groupBy = (arr, func) =>
arr.map(typeof func === 'function' ? func : val => val[func])
.reduce((acc, val, i) => { acc[val] = (acc[val] || []).concat(arr[i]); return acc; }, {});
// groupBy([6.1, 4.2, 6.3], Math.floor) -> {4: [4.2], 6: [6.1, 6.3]}
// groupBy(['one', 'two', 'three'], 'length') -> {3: ['one', 'two'], 5: ['three']}
Use arr[0]
to return the first element of the passed array.
const head = arr => arr[0];
// head([1,2,3]) -> 1
Use arr.slice(0,-1)
to return all but the last element of the array.
const initial = arr => arr.slice(0, -1);
// initial([1,2,3]) -> [1,2]
Use Array(end-start)
to create an array of the desired length, Array.map()
to fill with the desired values in a range.
You can omit start
to use a default value of 0
.
const initializeArrayRange = (end, start = 0) =>
Array.from({ length: end - start }).map((v, i) => i + start);
// initializeArrayRange(5) -> [0,1,2,3,4]
Use Array(n)
to create an array of the desired length, fill(v)
to fill it with the desired values.
You can omit value
to use a default value of 0
.
const initializeArray = (n, value = 0) => Array(n).fill(value);
// initializeArray(5, 2) -> [2,2,2,2,2]
Use arr.length - 1
to compute index of the last element of the given array and returning it.
const last = arr => arr[arr.length - 1];
// last([1,2,3]) -> 3
Find the middle of the array, use Array.sort()
to sort the values.
Return the number at the midpoint if length
is odd, otherwise the average of the two middle numbers.
const median = arr => {
const mid = Math.floor(arr.length / 2), nums = arr.sort((a, b) => a - b);
return arr.length % 2 !== 0 ? nums[mid] : (nums[mid - 1] + nums[mid]) / 2;
};
// median([5,6,50,1,-5]) -> 5
// median([0,10,-2,7]) -> 3.5
Use Array.slice()
to get an array containing the nth element at the first place.
If the index is out of bounds, return []
.
Omit the second argument, n
, to get the first element of the array.
const nth = (arr, n=0) => (n>0? arr.slice(n,n+1) : arr.slice(n))[0];
// nth(['a','b','c'],1) -> 'b'
// nth(['a','b','b']-2) -> 'a'
Use Array.reduce()
to convert the filtered/picked keys back to a object with the corresponding key:value pair if the key exist in the obj.
const pick = (obj, arr) =>
arr.reduce((acc, curr) => (curr in obj && (acc[curr] = obj[curr]), acc), {});
// pick({ 'a': 1, 'b': '2', 'c': 3 }, ['a', 'c']) -> { 'a': 1, 'c': 3 }
// pick(object, ['a', 'c'])['a'] -> 1
Use Array.sort()
to reorder elements, using Math.random()
in the comparator.
const shuffle = arr => arr.sort(() => Math.random() - 0.5);
// shuffle([1,2,3]) -> [2,3,1]
Use filter()
to remove values that are not part of values
, determined using includes()
.
const similarity = (arr, values) => arr.filter(v => values.includes(v));
// similarity([1,2,3], [1,2,4]) -> [1,2]
Use Array.reduce()
to add each value to an accumulator, initialized with a value of 0
.
const sum = arr => arr.reduce((acc, val) => acc + val, 0);
// sum([1,2,3,4]) -> 10
Return arr.slice(1)
if the array's length
is more than 1
, otherwise return the whole array.
const tail = arr => arr.length > 1 ? arr.slice(1) : arr;
// tail([1,2,3]) -> [2,3]
// tail([1]) -> [1]
Use Array.filter()
to create a new array that contains every nth element of a given array.
const everynth = (arr, nth) => arr.filter((e, i) => i % nth === 0);
// everynth([1,2,3,4,5,6], 2) -> [ 1, 3, 5 ]
Use Array.slice()
to create a slice of the array with n
elements taken from the end.
const takeRight = (arr, n = 1) => arr.slice(arr.length - n, arr.length);
// takeRight([1, 2, 3], 2) -> [ 2, 3 ]
// takeRight([1, 2, 3]) -> [3]
Use Array.slice()
to create a slice of the array with n
elements taken from the beginning.
const take = (arr, n = 1) => arr.slice(0, n);
// take([1, 2, 3], 5) -> [1, 2, 3]
// take([1, 2, 3], 0) -> []
Use ES6 Set
and the ...rest
operator to discard all duplicated values.
const unique = arr => [...new Set(arr)];
// unique([1,2,2,3,4,4,5]) -> [1,2,3,4,5]
Use scrollY
, scrollHeight
and clientHeight
to determine if the bottom of the page is visible.
const bottomVisible = () =>
document.documentElement.clientHeight + window.scrollY >= document.documentElement.scrollHeight || document.documentElement.clientHeight;
// bottomVisible() -> true
Use window.location.href
to get current URL.
const currentUrl = () => window.location.href;
// currentUrl() -> 'https://google.com'
Use Element.getBoundingClientRect()
and the window.inner(Width|Height)
values
to determine if a given element is visible in the viewport.
Omit the second argument to determine if the element is entirely visible, or specify true
to determine if
it is partially visible.
const elementIsVisibleInViewport = (el, partiallyVisible = false) => {
const { top, left, bottom, right } = el.getBoundingClientRect();
return partiallyVisible
? ((top > 0 && top < innerHeight) || (bottom > 0 && bottom < innerHeight)) &&
((left > 0 && left < innerWidth) || (right > 0 && right < innerWidth))
: top >= 0 && left >= 0 && bottom <= innerHeight && right <= innerWidth;
};
// e.g. 100x100 viewport and a 10x10px element at position {top: -1, left: 0, bottom: 9, right: 10}
// elementIsVisibleInViewport(el) -> false (not fully visible)
// elementIsVisibleInViewport(el, true) -> true (partially visible)
Use pageXOffset
and pageYOffset
if they are defined, otherwise scrollLeft
and scrollTop
.
You can omit el
to use a default value of window
.
const getScrollPos = (el = window) =>
({x: (el.pageXOffset !== undefined) ? el.pageXOffset : el.scrollLeft,
y: (el.pageYOffset !== undefined) ? el.pageYOffset : el.scrollTop});
// getScrollPos() -> {x: 0, y: 200}
Use window.location.href
or window.location.replace()
to redirect to url
.
Pass a second argument to simulate a link click (true
- default) or an HTTP redirect (false
).
const redirect = (url, asLink = true) =>
asLink ? window.location.href = url : window.location.replace(url);
// redirect('https://google.com')
Get distance from top using document.documentElement.scrollTop
or document.body.scrollTop
.
Scroll by a fraction of the distance from top. Use window.requestAnimationFrame()
to animate the scrolling.
const scrollToTop = () => {
const c = document.documentElement.scrollTop || document.body.scrollTop;
if (c > 0) {
window.requestAnimationFrame(scrollToTop);
window.scrollTo(0, c - c / 8);
}
};
// scrollToTop()
Use Date.toISOString()
, split('T')
and replace()
to convert a date from American format to English format.
Throws an error if the passed time cannot be converted to a date.
const toEnglishDate = (time) =>
{try{return new Date(time).toISOString().split('T')[0].replace(/-/g, '/')}catch(e){return}};
// toEnglishDate('09/21/2010') -> '21/09/2010'
Calculate the difference (in days) between to Date
objects.
const getDaysDiffBetweenDates = (dateInitial, dateFinal) => (dateFinal - dateInitial) / (1000 * 3600 * 24);
// getDaysDiffBetweenDates(new Date("2017-12-13"), new Date("2017-12-22")) -> 9
Use Date()
, to convert dates in JSON format to readable format (dd/mm/yyyy
).
const jsonToDate = arr => {
const dt = new Date(parseInt(arr.toString().substr(6)));
return `${ dt.getDate() }/${ dt.getMonth() + 1 }/${ dt.getFullYear() }`
};
// jsonToDate(/Date(1489525200000)/) -> "14/3/2017"
Loop through an array of functions containing asynchronous events, calling next
when each asynchronous event has completed.
const chainAsync = fns => { let curr = 0; const next = () => fns[curr++](next); next(); };
/*
chainAsync([
next => { console.log('0 seconds'); setTimeout(next, 1000); },
next => { console.log('1 second'); setTimeout(next, 1000); },
next => { console.log('2 seconds'); }
])
*/
Use Array.reduce()
to perform right-to-left function composition.
The last (rightmost) function can accept one or more arguments; the remaining functions must be unary.
const compose = (...fns) => fns.reduce((f, g) => (...args) => f(g(...args)));
/*
const add5 = x => x + 5
const multiply = (x, y) => x * y
const multiplyAndAdd5 = compose(add5, multiply)
multiplyAndAdd5(5, 2) -> 15
*/
Use recursion.
If the number of provided arguments (args
) is sufficient, call the passed function f
.
Otherwise return a curried function f
that expects the rest of the arguments.
If you want to curry a function that accepts a variable number of arguments (a variadic function, e.g. Math.min()
), you can optionally pass the number of arguments to the second parameter arity
.
const curry = (fn, arity = fn.length, ...args) =>
arity <= args.length
? fn(...args)
: curry.bind(null, fn, arity, ...args);
// curry(Math.pow)(2)(10) -> 1024
// curry(Math.min, 3)(10)(50)(2) -> 2
Use console.debug()
and the name
property of the passed method to log the method's name to the debug
channel of the console.
const functionName = fn => (console.debug(fn.name), fn);
// functionName(Math.max) -> max (logged in debug channel of console)
Use Array.reduce()
with the spread operator (...
) to perform left-to-right function composition.
The first (leftmost) function can accept one or more arguments; the remaining functions must be unary.
const pipe = (...fns) => fns.reduce((f, g) => (...args) => g(f(...args)));
/*
const add5 = x => x + 5
const multiply = (x, y) => x * y
const multiplyAndAdd5 = pipe(multiply, add5)
multiplyAndAdd5(5, 2) -> 15
*/
Use currying to return a function returning a Promise
that calls the original function.
Use the ...rest
operator to pass in all the parameters.
In Node 8+, you can use util.promisify
const promisify = func =>
(...args) =>
new Promise((resolve, reject) =>
func(...args, (err, result) =>
err ? reject(err) : resolve(result))
);
// const delay = promisify((d, cb) => setTimeout(cb, d))
// delay(2000).then(() => console.log('Hi!')) -> Promise resolves after 2s
Run an array of promises in series using Array.reduce()
by creating a promise chain, where each promise returns the next promise when resolved.
const series = ps => ps.reduce((p, next) => p.then(next), Promise.resolve());
// const delay = (d) => new Promise(r => setTimeout(r, d))
// series([() => delay(1000), () => delay(2000)]) -> executes each promise sequentially, taking a total of 3 seconds to complete
Delay executing part of an async
function, by putting it to sleep, returning a Promise
.
const sleep = ms => new Promise(resolve => setTimeout(resolve, ms));
/*
async function sleepyWork() {
console.log('I\'m going to sleep for 1 second.');
await sleep(1000);
console.log('I woke up after 1 second.');
}
*/
If n
is even, return n/2
. Otherwise return 3n+1
.
const collatz = n => (n % 2 == 0) ? (n / 2) : (3 * n + 1);
// collatz(8) --> 4
// collatz(5) --> 16
Use Math.hypot()
to calculate the Euclidean distance between two points.
const distance = (x0, y0, x1, y1) => Math.hypot(x1 - x0, y1 - y0);
// distance(1,1, 2,3) -> 2.23606797749979
Use the modulo operator (%
) to check if the remainder is equal to 0
.
const isDivisible = (dividend, divisor) => dividend % divisor === 0;
// isDivisible(6,3) -> true
Checks whether a number is odd or even using the modulo (%
) operator.
Returns true
if the number is even, false
if the number is odd.
const isEven = num => num % 2 === 0;
// isEven(3) -> false
Use recursion.
If n
is less than or equal to 1
, return 1
.
Otherwise, return the product of n
and the factorial of n - 1
.
Throws an exception if n
is a negative number.
const factorial = n =>
n < 0 ? (() => { throw new TypeError('Negative numbers are not allowed!') })()
: n <= 1 ? 1 : n * factorial(n - 1);
// factorial(6) -> 720
Create an empty array of the specific length, initializing the first two values (0
and 1
).
Use Array.reduce()
to add values into the array, using the sum of the last two values, except for the first two.
const fibonacci = n =>
Array(n).fill(0).reduce((acc, val, i) => acc.concat(i > 1 ? acc[i - 1] + acc[i - 2] : i), []);
// fibonacci(5) -> [0,1,1,2,3]
Use recursion.
Base case is when y
equals 0
. In this case, return x
.
Otherwise, return the GCD of y
and the remainder of the division x/y
.
const gcd = (x, y) => !y ? x : gcd(y, x % y);
// gcd (8, 36) -> 4
Use XOR operator (^
) to find the bit difference between the two numbers, convert to binary string using toString(2)
.
Count and return the number of 1
s in the string, using match(/1/g)
.
const hammingDistance = (num1, num2) =>
((num1 ^ num2).toString(2).match(/1/g) || '').length;
// hammingDistance(2,3) -> 1
Use the greatest common divisor (GCD) formula and Math.abs()
to determine the least common multiple.
The GCD formula uses recursion.
const lcm = (x,y) => {
const gcd = (x, y) => !y ? x : gcd(y, x % y);
return Math.abs(x*y)/(gcd(x,y));
};
// lcm(12,7) -> 84
Use Array.reduce()
to calculate how many numbers are below the value and how many are the same value and
apply the percentile formula.
const percentile = (arr, val) =>
100 * arr.reduce((acc,v) => acc + (v < val ? 1 : 0) + (v === val ? 0.5 : 0), 0) / arr.length;
// percentile([1,2,3,4,5,6,7,8,9,10], 6) -> 55
Use Array.reduce()
combined with Array.map()
to iterate over elements and combine into an array containing all combinations.
const powerset = arr =>
arr.reduce((a, v) => a.concat(a.map(r => [v].concat(r))), [[]]);
// powerset([1,2]) -> [[], [1], [2], [2,1]]
Use Math.random()
to generate a random number and map it to the desired range, using Math.floor()
to make it an integer.
const randomIntegerInRange = (min, max) => Math.floor(Math.random() * (max - min + 1)) + min;
// randomIntegerInRange(0, 5) -> 2
Use Math.random()
to generate a random value, map it to the desired range using multiplication.
const randomInRange = (min, max) => Math.random() * (max - min) + min;
// randomInRange(2,10) -> 6.0211363285087005
Use Math.round()
and template literals to round the number to the specified number of digits.
Omit the second argument, decimals
to round to an integer.
const round = (n, decimals=0) => Number(`${Math.round(`${n}e${decimals}`)}e-${decimals}`);
// round(1.005, 2) -> 1.01
Use Array.reduce()
to calculate the mean, variance and the sum of the variance of the values, the variance of the values, then
determine the standard deviation.
You can omit the second argument to get the sample standard deviation or set it to true
to get the population standard deviation.
const standardDeviation = (arr, usePopulation = false) => {
const mean = arr.reduce((acc, val) => acc + val, 0) / arr.length;
return Math.sqrt(
arr.reduce((acc, val) => acc.concat(Math.pow(val - mean, 2)), [])
.reduce((acc, val) => acc + val, 0) / (arr.length - (usePopulation ? 0 : 1))
);
};
// standardDeviation([10,2,38,23,38,23,21]) -> 13.284434142114991 (sample)
// standardDeviation([10,2,38,23,38,23,21], true) -> 12.29899614287479 (population)
Use SpeechSynthesisUtterance.voice
and window.speechSynthesis.getVoices()
to convert a message to speech.
Use window.speechSynthesis.speak()
to play the message.
Learn more about the SpeechSynthesisUtterance interface of the Web Speech API.
const speak = message => {
const msg = new SpeechSynthesisUtterance(message);
msg.voice = window.speechSynthesis.getVoices()[0];
window.speechSynthesis.speak(msg);
};
// speak('Hello, World') -> plays the message
Use readFileSync
function in fs
node package to create a Buffer
from a file.
convert buffer to string using toString(encoding)
function.
creating an array from contents of file by split
ing file content line by line(each \n
).
const fs = require('fs');
const readFileToArray = filename => fs.readFileSync(filename).toString('UTF8').split('\n');
/*
contents of test.txt :
line1
line2
line3
___________________________
let arr = readFileToArray('test.txt')
console.log(arr) // -> ['line1', 'line2', 'line3']
*/
Use fs.writeFile()
, template literals and JSON.stringify()
to write a json
object to a .json
file.
const fs = require('fs');
const jsonToFile = (obj, filename) => fs.writeFile(`${filename}.json`, JSON.stringify(obj, null, 2))
// jsonToFile({test: "is passed"}, 'testJsonFile') -> writes the object to 'testJsonFile.json'
Use Object.keys()
method to loop over given json object and deleting keys that are not include
d in given array.
also if you give it a special key(childIndicator
) it will search deeply inside it to apply function to inner objects too.
const cleanObj = (obj, keysToKeep = [], childIndicator) => {
Object.keys(obj).forEach(key => {
if (key === childIndicator) {
cleanObj(obj[key], keysToKeep, childIndicator);
} else if (!keysToKeep.includes(key)) {
delete obj[key];
}
})
}
/*
testObj = {a: 1, b: 2, children: {a: 1, b: 2}}
cleanObj(testObj, ["a"],"children")
console.log(testObj)// { a: 1, children : { a: 1}}
*/
Use Array.reduce()
to create and combine key-value pairs.
const objectFromPairs = arr => arr.reduce((a, v) => (a[v[0]] = v[1], a), {});
// objectFromPairs([['a',1],['b',2]]) -> {a: 1, b: 2}
Use Object.keys()
and Array.map()
to iterate over the object's keys and produce an array with key-value pairs.
const objectToPairs = obj => Object.keys(obj).map(k => [k, obj[k]]);
// objectToPairs({a: 1, b: 2}) -> [['a',1],['b',2]])
Use Object.assign()
and an empty object ({}
) to create a shallow clone of the original.
const shallowClone = obj => Object.assign({}, obj);
/*
const a = { x: true, y: 1 };
const b = shallowClone(a);
a === b -> false
*/
Use recursion.
For each letter in the given string, create all the partial anagrams for the rest of its letters.
Use Array.map()
to combine the letter with each partial anagram, then Array.reduce()
to combine all anagrams in one array.
Base cases are for string length
equal to 2
or 1
.
const anagrams = str => {
if (str.length <= 2) return str.length === 2 ? [str, str[1] + str[0]] : [str];
return str.split('').reduce((acc, letter, i) =>
acc.concat(anagrams(str.slice(0, i) + str.slice(i + 1)).map(val => letter + val)), []);
};
// anagrams('abc') -> ['abc','acb','bac','bca','cab','cba']
Use replace()
to match the first character of each word and toUpperCase()
to capitalize it.
const capitalizeEveryWord = str => str.replace(/\b[a-z]/g, char => char.toUpperCase());
// capitalizeEveryWord('hello world!') -> 'Hello World!'
Use destructuring and toUpperCase()
to capitalize first letter, ...rest
to get array of characters after first letter and then Array.join('')
to make it a string again.
Omit the lowerRest
parameter to keep the rest of the string intact, or set it to true
to convert to lower case.
const capitalize = ([first,...rest], lowerRest = false) =>
first.toUpperCase() + (lowerRest ? rest.join('').toLowerCase() : rest.join(''));
// capitalize('myName') -> 'MyName'
// capitalize('myName', true) -> 'Myname'
Convert string toLowerCase()
and use replace()
to remove non-alphanumeric characters from it.
Then, split('')
into individual characters, reverse()
, join('')
and compare to the original, unreversed string, after converting it tolowerCase()
.
const palindrome = str => {
const s = str.toLowerCase().replace(/[\W_]/g,'');
return s === s.split('').reverse().join('');
}
// palindrome('taco cat') -> true
Use replace()
to remove underscores, hyphens and spaces and convert words to camelcase.
Omit the scond argument to use a default separator of '_'.
const fromCamelCase = (str, separator = '_') =>
str.replace(/([a-z\d])([A-Z])/g, '$1' + separator + '$2')
.replace(/([A-Z]+)([A-Z][a-z\d]+)/g, '$1' + separator + '$2').toLowerCase();
// fromCamelCase('someDatabaseFieldName', ' ') -> 'some database field name'
// fromCamelCase('someLabelThatNeedsToBeCamelized', '-') -> 'some-label-that-needs-to-be-camelized'
// fromCamelCase('someJavascriptProperty', '_') -> 'some_javascript_property'
Use replace()
to remove underscores, hyphens and spaces and convert words to camelcase.
const toCamelCase = str =>
str.replace(/^([A-Z])|[\s-_]+(\w)/g, (match, p1, p2, offset) => p2 ? p2.toUpperCase() : p1.toLowerCase());
// toCamelCase("some_database_field_name") -> 'someDatabaseFieldName'
// toCamelCase("Some label that needs to be camelized") -> 'someLabelThatNeedsToBeCamelized'
// toCamelCase("some-javascript-property") -> 'someJavascriptProperty'
// toCamelCase("some-mixed_string with spaces_underscores-and-hyphens") -> 'someMixedStringWithSpacesUnderscoresAndHyphens'
Use array destructuring and Array.reverse()
to reverse the order of the characters in the string.
Combine characters to get a string using join('')
.
const reverseString = str => [...str].reverse().join('');
// reverseString('foobar') -> 'raboof'
Split the string using split('')
, Array.sort()
utilizing localeCompare()
, recombine using join('')
.
const sortCharactersInString = str =>
str.split('').sort((a, b) => a.localeCompare(b)).join('');
// sortCharactersInString('cabbage') -> 'aabbceg'
Determine if the string's length
is greater than num
.
Return the string truncated to the desired length, with ...
appended to the end or the original string.
const truncate = (str, num) =>
str.length > num ? str.slice(0, num > 3 ? num - 3 : num) + '...' : str;
// truncate('boomerang', 7) -> 'boom...'
Use Array.map()
, split()
and Array.join()
to join the mapped array for converting a three-digit RGB notated hexadecimal color-code to the six-digit form.
Array.slice()
is used to remove #
from string start since it's added once.
const convertHex = shortHex =>
'#' + shortHex.slice(shortHex.startsWith('#') ? 1 : 0).split().map(x => x+x).join()
// convertHex('#03f') -> '#0033ff'
// convertHex('05a') -> '#0055aa'
Use replace()
to escape special characters.
const escapeRegExp = str => str.replace(/[.*+?^${}()|[\]\\]/g, '\\$&');
// escapeRegExp('(test)') -> \\(test\\)
Returns lower-cased constructor name of value, "undefined" or "null" if value is undefined or null
const getType = v =>
v === undefined ? 'undefined' : v === null ? 'null' : v.constructor.name.toLowerCase();
// getType(new Set([1,2,3])) -> "set"
Use bitwise right-shift operator and mask bits with &
(and) operator to convert a hexadecimal color code (prefixed with #
) to a string with the RGB values.
const hexToRgb = hex => {
const h = parseInt(hex.slice(1), 16);
return `rgb(${h >> 16}, ${(h & 0x00ff00) >> 8}, ${h & 0x0000ff})`;
}
// hexToRgb('#27ae60') -> 'rgb(39, 174, 96)'
Use Array.isArray()
to check if a value is classified as an array.
const isArray = val => !!val && Array.isArray(val);
// isArray(null) -> false
// isArray([1]) -> true
Use typeof
to check if a value is classified as a boolean primitive.
const isBoolean = val => typeof val === 'boolean';
// isBoolean(null) -> false
// isBoolean(false) -> true
Use typeof
to check if a value is classified as a function primitive.
const isFunction = val => val && typeof val === 'function';
// isFunction('x') -> false
// isFunction(x => x) -> true
Use typeof
to check if a value is classified as a number primitive.
const isNumber = val => typeof val === 'number';
// isNumber('1') -> false
// isNumber(1) -> true
Use typeof
to check if a value is classified as a string primitive.
const isString = val => typeof val === 'string';
// isString(10) -> false
// isString('10') -> true
Use typeof
to check if a value is classified as a symbol primitive.
const isSymbol = val => typeof val === 'symbol';
// isSymbol('x') -> false
// isSymbol(Symbol('x')) -> true
Use console.time()
and console.timeEnd()
to measure the difference between the start and end times to determine how long the callback took to execute.
const timeTaken = callback => {
console.time('timeTaken');
const r = callback();
console.timeEnd('timeTaken');
return r;
};
// timeTaken(() => Math.pow(2, 10)) -> 1024
// (logged): timeTaken: 0.02099609375ms
Convert the number to a string, using spread operators in ES6([...string]
) build an array.
Use Array.map()
and parseInt()
to transform each value to an integer.
const digitize = n => [...''+n].map(i => parseInt(i));
// digitize(2334) -> [2, 3, 3, 4]
Use the modulo operator (%
) to find values of single and tens digits.
Find which ordinal pattern digits match.
If digit is found in teens pattern, use teens ordinal.
const toOrdinalSuffix = num => {
const int = parseInt(num), digits = [(int % 10), (int % 100)],
ordinals = ['st', 'nd', 'rd', 'th'], oPattern = [1, 2, 3, 4],
tPattern = [11, 12, 13, 14, 15, 16, 17, 18, 19];
return oPattern.includes(digits[0]) && !tPattern.includes(digits[1]) ? int + ordinals[digits[0] - 1] : int + ordinals[3];
};
// toOrdinalSuffix("123") -> "123rd"
Convert given RGB parameters to hexadecimal string using bitwise left-shift operator (<<
) and toString(16)
, then padStart(6,'0')
to get a 6-digit hexadecimal value.
const rgbToHex = (r, g, b) => ((r << 16) + (g << 8) + b).toString(16).padStart(6, '0');
// rgbToHex(255, 165, 1) -> 'ffa501'
Use match()
with an appropriate regular expression to get all key-value pairs, Array.reduce()
to map and combine them into a single object.
Pass location.search
as the argument to apply to the current url
.
const getUrlParameters = url =>
url.match(/([^?=&]+)(=([^&]*))/g).reduce(
(a, v) => (a[v.slice(0, v.indexOf('='))] = v.slice(v.indexOf('=') + 1), a), {}
);
// getUrlParameters('http://url.com/page?name=Adam&surname=Smith') -> {name: 'Adam', surname: 'Smith'}
Use crypto
API to generate a UUID, compliant with RFC4122 version 4.
const uuid = () =>
([1e7] + -1e3 + -4e3 + -8e3 + -1e11).replace(/[018]/g, c =>
(c ^ crypto.getRandomValues(new Uint8Array(1))[0] & 15 >> c / 4).toString(16)
);
// uuid() -> '7982fcfe-5721-4632-bede-6000885be57d'
Use a regular expression to check if the email is valid.
Returns true
if email is valid, false
if not.
const validateEmail = str =>
/^(([^<>()\[\]\\.,;:\s@"]+(\.[^<>()\[\]\\.,;:\s@"]+)*)|(".+"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/.test(str);
// validateEmail([email protected]) -> true
Use !isNaN
in combination with parseFloat()
to check if the argument is a number.
Use isFinite()
to check if the number is finite.
Use Number()
to check if the coercion holds.
const validateNumber = n => !isNaN(parseFloat(n)) && isFinite(n) && Number(n) == n;
// validateNumber('10') -> true
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