[최단경로] 2176300 이지현 #349
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[최단경로] 2176300 이지현 #349
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코드리뷰완료 |
Dong-droid
reviewed
May 30, 2023
Comment on lines
+63
to
+64
| vector<int> go = dijkstra(x, n, rev_graph); // 모든 정점에서 x로 가는 최단 경로 | ||
| vector<int> back = dijkstra(x, n, graph); // x에서 모든 정점까지 가는 최단 경로 |
Dong-droid
reviewed
May 30, 2023
Comment on lines
+53
to
+65
| for (int i = 1; i <= n; i++) | ||
| { | ||
| int cnt = 0; | ||
| for (int j = 1; j <= n; j++) | ||
| { | ||
| if (h[i][j] != INF || h[j][i] != INF) | ||
| { // i번, j번 학생 키의 대소관계를 아는 경우 | ||
| cnt++; | ||
| } | ||
| } | ||
| if (cnt == n - 1) // 자기를 제외한 모든 사람과의 비교가 완료된 경우 | ||
| ans++; // ans ++ | ||
| } |
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인적사항
학번: 2176300
이름: 이지현
과제 제출
기존 제출 : 1238, 2458
추가 제출 :