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Goldchae
approved these changes
Oct 1, 2023
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| pair<int, int> plainGround(int n, int m, int b, vector<vector<int>>& ground, int vmin, int vmax){ | ||
| int mintime = 256*500*500*2, maxheight = 0; |
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최댓값을 계산해주신 점 좋습니다! 하지만 더 안전한 방법으로 c++에서 최댓값(INF)을 다루는 여러 가지 방법에 대해 찾아보셔도 좋을 것 같네요!
| int mintime = 256*500*500*2, maxheight = 0; | ||
| for(int h=vmin; h<=vmax; h++){ //땅의 높이는 vmin~vmax까지 가능 | ||
| int add = 0, rm = 0; //더하는 블록의 수, 빼는 블록의 수 | ||
| for(int i=0; i<n; i++){ |
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| } | ||
| } | ||
| pair<int, int> ans = plainGround(n, m, b, ground, vmin, vmax); |
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많이 쓰이는 자료형은 typedef를 이용해서 별칭 지정해보시는 건 어떨까요?
chae-jpg
approved these changes
Oct 1, 2023
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| if(odd_info.first>1) { | ||
| cout << "I'm Sorry Hansoo"; | ||
| return 0; | ||
| } |
| } | ||
| } | ||
| string reverse_ans = ans; | ||
| reverse(reverse_ans.begin(), reverse_ans.end()); |
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| string palindrome(const vector<int>& alpha, int mid_idex){ |
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| if(speed[i]<speed[i+1]){ | ||
| //다음 행성까지의 속도 < 현재속도 * n을 만족하는 최소값 | ||
| //시간 초과 문제 발생 -> 반복문으로 계산하지 않는다. | ||
| if(speed[i+1]%speed[i]==0){ //배수관계인 경우 | ||
| speed[i] = speed[i+1]; | ||
| } | ||
| else{ //배수관계가 아닌 경우 | ||
| speed[i] = speed[i] * (speed[i+1] / speed[i] + 1); | ||
| } | ||
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| } |
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인적사항
학번 : 1876263
이름 : 이도현
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기존 제출 : 18111, 1213, 17451
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