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Goldchae
approved these changes
Oct 1, 2023
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| using namespace std; | ||
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| typedef pair<int, int> pii; //다음 pair의 이름을 pii로 선언 |
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| for (int i = 0; i < n; i++) { //전달받은 n번 동안 반복 | ||
| for (int j = 0; j < m; j++) { //전달받은 m번 동안 반복 | ||
| int gap = abs(height - blocks[i][j]); //목표한 높이와 블록의 차를 변수에 넣기 |
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| pii answer = makeGroundEven(n, m, b, ground); //땅을 고르게 만드는 데 드는 비용과 그 높이를 연산 | ||
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| cout << answer.first << " " << answer.second << "\n"; //결과 출력 |
chae-jpg
approved these changes
Oct 1, 2023
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| using namespace std; | ||
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| int arr[300000]; |
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P2
알튜비튜에서는 정말 필요한 경우를 제외하고는 전역변수 사용을 지양하고 있습니다! 이 경우에는 메인 함수 안에서 배열을 선언해도 문제를 해결할 수 있을 것처럼 보이네요!
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| using namespace std; | ||
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| int alphabet[26]; |
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P2
마찬가지로 알튜비튜에서는 정말 필요한 경우를 제외하고는 전역변수 사용을 지양하고 있습니다! 이 경우에는 메인 함수 안에서 배열을 선언하고 인자를 넘겨주면 충분히 문제를 해결할 수 있을 것 같아요!
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| if(count>1){ | ||
| return false; |
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| else{ | ||
| answer=makePd(mid); | ||
| } |
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P3
이 경우에는 위 경우를 만족하면 리턴되고 있으니 else를 붙이지 않아도 됩니다!
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| for(int i=n-2;i>=0;i--){ | ||
| if(answer%arr[i]==0){ | ||
| continue; | ||
| } | ||
| else{ | ||
| answer = (answer / arr[i] + 1) * arr[i]; | ||
| } | ||
| } |
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