Sample Assignment

Here is a sample assignment for testing MySui Online Judge. Add this assignment by clicking on Add in Assignments page.

Problems

This assignment has three problems:

Problem 1 (Sum):

Read integer n, and then read n integers. Print sum of these n numbers.

Sample Input	Sample Output
5 54 78 0 4 9	145

Problem 2 (Max):

Read integer n, and then read n integers. Print sum of the two largest numbers between these n numbers.

Sample Input	Sample Output
7 162 173 159 164 181 158 175	356

Problem 3 (Upload!):

Upload a c or zip file! (This problem is "Upload Only", and will not be judged)

Tests

Tests follow this structure.

You can find the zip file of the tests in Assignments folder.

The tree of this file is:

.
├── p1
│   ├── in
│   │   ├── input1.txt
│   │   ├── input2.txt
│   │   ├── input3.txt
│   │   ├── input4.txt
│   │   ├── input5.txt
│   │   ├── input6.txt
│   │   ├── input7.txt
│   │   ├── input8.txt
│   │   ├── input9.txt
│   │   └── input10.txt
│   ├── out
│   │   └── output1.txt
│   ├── tester.cpp
│   └── desc.md
├── p2
│   ├── in
│   │   ├── input1.txt
│   │   ├── input2.txt
│   │   ├── input3.txt
│   │   ├── input4.txt
│   │   ├── input5.txt
│   │   ├── input6.txt
│   │   ├── input7.txt
│   │   ├── input8.txt
│   │   ├── input9.txt
│   │   └── input10.txt
│   ├── out
│   │   ├── output1.txt
│   │   ├── output2.txt
│   │   ├── output3.txt
│   │   ├── output4.txt
│   │   ├── output5.txt
│   │   ├── output6.txt
│   │   ├── output7.txt
│   │   ├── output8.txt
│   │   ├── output9.txt
│   │   └── output10.txt
│   ├── desc.md
│   └── Problem2.pdf
├── p3
│   └── desc.md
└── SampleAssignment.pdf

Problem 1 uses "Tester" method for checking output. So it has a file tester.cpp (the Tester Script)

Problem 2 uses "Output Comparison" method for checking output. So it has two folders in and out containing test cases.

Problem 3 is an "Upload-Only" problem.

Sample Solutions

Sample solutions for problem 1:

C

#include<stdio.h>
int main(){
	int n;
	scanf("%d",&n);
	int i;
	int sum =0 ;
	int k;
	for(i=0 ; i<n ; i++){
		scanf("%d",&k);
		sum+=k;
	}
	printf("%d\n",sum);
	return 0;
}

C++

#include <iostream>
using namespace std;
int main(){
	int n, sum=0;
	cin >> n;
	for (int i=0 ; i<n ; i++){
		int a;
		cin >> a;
		sum += a;
	}
	cout << sum << endl;
	return 0;
}

Java

import java.util.Scanner;
class sum
{
	public static void main(String[] args)
	{ 
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int sum =0;
		for (int i=0 ; i<n ; i++)
		{
			int a = sc.nextInt();
			sum += a;
		}
		System.out.println(sum); 
	}
}

Sample Solution for problem 2:

C

#include<stdio.h>
int main(){
	int n , m1=0, m2=0;
	scanf("%d",&n);
	for(;n--;){
		int k;
		scanf("%d",&k);
		if(k>=m1){
			m2=m1;
			m1=k;
		}
		else if(k>m2)
			m2=k;
	}
	printf("%d",m1+m2);
	return 0;
}

C++

#include<iostream>
using namespace std;
int main(){
	int n , m1=0, m2=0;
	cin >> n;
	for(;n--;){
		int k;
		cin >> k;
		if(k>=m1){
			m2=m1;
			m1=k;
		}
		else if(k>m2)
			m2=k;
	}
	cout << (m1+m2) << endl ;
	return 0;
}