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Leaves - Katie K #38
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Leaves - Katie K #38
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Overall nice work, you hit the learning goals here. Well done. Do take a look at my comments.
if current >= 3 | ||
look_up[current] = look_up[current-1] + look_up[current-2] | ||
look_up.delete(current - 2) |
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Clever
@@ -3,6 +3,39 @@ | |||
# Time Complexity - ? | |||
# Space Complexity - ? (should be O(n)) | |||
# Hint, you may want a recursive helper method | |||
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def fibonacci(n) |
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👍
# Time Complexity - ? | ||
# Space Complexity - ? (should be O(n)) |
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no answer here?
@@ -3,13 +3,27 @@ | |||
# Time Complexity - ? | |||
# Space Complexity - ? | |||
def super_digit(n) |
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👍 but no time/space complexity?
return super_digit(sum) | ||
end | ||
end | ||
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# Time Complexity - ? | ||
# Space Complexity - ? | ||
def refined_super_digit(n, k) |
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👍 But you can go further with dynamic programming.
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