Dominique - Leaves #26
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CheezItMan
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Nov 20, 2019
| # Time Complexity - ? | ||
| # Space Complexity - ? (should be O(n)) | ||
| # Time Complexity - O(n!) | ||
| # Space Complexity O(n) | ||
| # Hint, you may want a recursive helper method | ||
| def fibonacci(n) |
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This is the brute force O(2n) time complexity solution...
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| # Time Complexity - O(n) | ||
| # Space Complexity - O(n) | ||
| def super_digit(x) |
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| # Time Complexity - O(n) | ||
| # Space Complexity - O(n) |
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Yes, where n is the number of digits.
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