Segmentation Fault when running rbeast in a for-loop with hasOutlier=True

[marinasie]

Hi everyone,

I've been using your algorithm to detect change points in bird populations, and I'm loving the results so far!

When I run BEAST like this without a for-loop, it works perfectly:
o = rb.beast(y, deltat='7 days', period='1 year', hasOutlier=True)
However, when I introduce a for-loop around it to calculate change points for multiple time series, the first iteration executes without any issues, but I encounter a segmentation fault during the second iteration. With hasOutlier=False, the loop works fine.

I'm using the latest version of the Python package on my Mac, and all my time series have a length of 260.

Do you have any suggestions on how I might resolve this issue?
Thank you!

[dirt]

Marina, Thanks for the important feedback. Unfortunately there is no way to tell what went wrong without reproducing the error on my end. If possible, can you share a sample dataset plus the failing script for me to test-run it and figure out the cause? Thanks. Kaiguang

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________________________________ From: Marina Siebold ***@***.***> Sent: Friday, August 2, 2024 5:06 AM To: zhaokg/Rbeast ***@***.***> Cc: Subscribed ***@***.***> Subject: [zhaokg/Rbeast] Segmentation Fault when running rbeast in a for-loop (Issue #32) Hi everyone, I've been using your algorithm to detect change points in bird populations, and I'm loving the results so far! When I run BEAST without a for-loop, it works perfectly. However, when I introduce a for-loop around o = rb. beast(. . . ) Hi everyone, I've been using your algorithm to detect change points in bird populations, and I'm loving the results so far! When I run BEAST without a for-loop, it works perfectly. However, when I introduce a for-loop around o = rb.beast(...) to calculate change points for multiple time series, the first iteration executes without any issues, but I encounter a segmentation fault during the second iteration. I'm using the latest version of the Python package on my Mac, and all my time series have a length of 260. Do you have any suggestions on how I might resolve this issue? Thank you! — Reply to this email directly, view it on GitHub<https://urldefense.com/v3/__https://github.com/zhaokg/Rbeast/issues/32__;!!KGKeukY!xJlnrVg2XlX9kExmpsNWQa_fEEkC_8Yoh2Z7KPdkB7Y1ZtS0qEXwAx33GJCzUtu4X0ssWlK_HpdnrLJJfIsyKshiRDwt$>, or unsubscribe<https://urldefense.com/v3/__https://github.com/notifications/unsubscribe-auth/AMCAGWSDPKZ6L76AMIALZ6LZPND2NAVCNFSM6AAAAABL4EUD36VHI2DSMVQWIX3LMV43ASLTON2WKOZSGQ2DINBWHEZTAOI__;!!KGKeukY!xJlnrVg2XlX9kExmpsNWQa_fEEkC_8Yoh2Z7KPdkB7Y1ZtS0qEXwAx33GJCzUtu4X0ssWlK_HpdnrLJJfIsyKk7m481I$>. You are receiving this because you are subscribed to this thread.Message ID: ***@***.***>

[dirt]

Sorry. I forgot to mention that you can directly communicate with me at ***@***.*** Thanks. Kaiguang

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________________________________ From: Marina Siebold ***@***.***> Sent: Friday, August 2, 2024 5:06 AM To: zhaokg/Rbeast ***@***.***> Cc: Subscribed ***@***.***> Subject: [zhaokg/Rbeast] Segmentation Fault when running rbeast in a for-loop (Issue #32) Hi everyone, I've been using your algorithm to detect change points in bird populations, and I'm loving the results so far! When I run BEAST without a for-loop, it works perfectly. However, when I introduce a for-loop around o = rb. beast(. . . ) Hi everyone, I've been using your algorithm to detect change points in bird populations, and I'm loving the results so far! When I run BEAST without a for-loop, it works perfectly. However, when I introduce a for-loop around o = rb.beast(...) to calculate change points for multiple time series, the first iteration executes without any issues, but I encounter a segmentation fault during the second iteration. I'm using the latest version of the Python package on my Mac, and all my time series have a length of 260. Do you have any suggestions on how I might resolve this issue? Thank you! — Reply to this email directly, view it on GitHub<https://urldefense.com/v3/__https://github.com/zhaokg/Rbeast/issues/32__;!!KGKeukY!xJlnrVg2XlX9kExmpsNWQa_fEEkC_8Yoh2Z7KPdkB7Y1ZtS0qEXwAx33GJCzUtu4X0ssWlK_HpdnrLJJfIsyKshiRDwt$>, or unsubscribe<https://urldefense.com/v3/__https://github.com/notifications/unsubscribe-auth/AMCAGWSDPKZ6L76AMIALZ6LZPND2NAVCNFSM6AAAAABL4EUD36VHI2DSMVQWIX3LMV43ASLTON2WKOZSGQ2DINBWHEZTAOI__;!!KGKeukY!xJlnrVg2XlX9kExmpsNWQa_fEEkC_8Yoh2Z7KPdkB7Y1ZtS0qEXwAx33GJCzUtu4X0ssWlK_HpdnrLJJfIsyKk7m481I$>. You are receiving this because you are subscribed to this thread.Message ID: ***@***.***>

[marinasie]

Thank you very much! I contacted you via email 😊

[dirt]

HI Marina, Thanks. I didn't get any other messages from you about the sample data or crashing script. My working email is ***@***.*** Best, Kaiguang

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________________________________ From: Marina Siebold ***@***.***> Sent: Monday, August 5, 2024 7:22 AM To: zhaokg/Rbeast ***@***.***> Cc: Zhao, Kaiguang ***@***.***>; Comment ***@***.***> Subject: Re: [zhaokg/Rbeast] Segmentation Fault when running rbeast in a for-loop with hasOutlier=True (Issue #32) Thank you very much! I contacted you via email 😊 — Reply to this email directly, view it on GitHub, or unsubscribe. You are receiving this because you commented. Message ID: <zhaokg/Rbeast/issues/32/2268835604@ github. com> ‍ ‍ ‍ ‍ ‍ ‍ ‍ Thank you very much! I contacted you via email 😊 — Reply to this email directly, view it on GitHub<https://urldefense.com/v3/__https://github.com/zhaokg/Rbeast/issues/32*issuecomment-2268835604__;Iw!!KGKeukY!3jqQseI3x9iL6oWQvXAZLt8iw-Ej9tVjKlmNizy71SqumvhXSzqFkx54tNflDwN2MoOpmrztyWUO3pYAksSmgOWQ3JFh$>, or unsubscribe<https://urldefense.com/v3/__https://github.com/notifications/unsubscribe-auth/AMCAGWWNFEGUKV2V637WEVLZP5N7NAVCNFSM6AAAAABL4EUD36VHI2DSMVQWIX3LMV43OSLTON2WKQ3PNVWWK3TUHMZDENRYHAZTKNRQGQ__;!!KGKeukY!3jqQseI3x9iL6oWQvXAZLt8iw-Ej9tVjKlmNizy71SqumvhXSzqFkx54tNflDwN2MoOpmrztyWUO3pYAksSmgBQQF7-V$>. You are receiving this because you commented.Message ID: ***@***.***>

[zhaokg]

Thank you very much! I contacted you via email 😊

My email is [email protected].

[marinasie]

Thank you! @zhaokg I contacted you, could you forward it to @dirt ? :)

[zhaokg]

Thank you! @zhaokg I contacted you, could you forward it to @dirt ? :)

Sorry. @dirt ([email protected], my working emall) and @zhaokg ([email protected], personal email) is the same person. It is me. Sorry about the confusion I checked both the email boxes, and didn't see anything from you.

Thanks,

[marinasie]

I resent it to your personal email, I hope it reached you well. :)