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感觉可以根据word2vec原论文中的那个负采样概率公式得到每个id的采样概率,然后根据概率采样几个负样本更好(比如alias采样)?
The text was updated successfully, but these errors were encountered:
num_classes=self.num_nodes, = args.num_feat 感觉是不是不太合理啊,正例数才4
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感觉可以根据word2vec原论文中的那个负采样概率公式得到每个id的采样概率,然后根据概率采样几个负样本更好(比如alias采样)?
The text was updated successfully, but these errors were encountered: