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New Problem Solution "Add to Array-Form of Integer"
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algorithms/cpp/addToArrayFormOfInteger/AddToArrayFormOfInteger.cpp
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// Source : https://leetcode.com/problems/add-to-array-form-of-integer/ | ||
// Author : Hao Chen | ||
// Date : 2019-03-25 | ||
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/***************************************************************************************************** | ||
* | ||
* For a non-negative integer X, the array-form of X is an array of its digits in left to right order. | ||
* For example, if X = 1231, then the array form is [1,2,3,1]. | ||
* | ||
* Given the array-form A of a non-negative integer X, return the array-form of the integer X+K. | ||
* | ||
* Example 1: | ||
* | ||
* Input: A = [1,2,0,0], K = 34 | ||
* Output: [1,2,3,4] | ||
* Explanation: 1200 + 34 = 1234 | ||
* | ||
* Example 2: | ||
* | ||
* Input: A = [2,7,4], K = 181 | ||
* Output: [4,5,5] | ||
* Explanation: 274 + 181 = 455 | ||
* | ||
* Example 3: | ||
* | ||
* Input: A = [2,1,5], K = 806 | ||
* Output: [1,0,2,1] | ||
* Explanation: 215 + 806 = 1021 | ||
* | ||
* Example 4: | ||
* | ||
* Input: A = [9,9,9,9,9,9,9,9,9,9], K = 1 | ||
* Output: [1,0,0,0,0,0,0,0,0,0,0] | ||
* Explanation: 9999999999 + 1 = 10000000000 | ||
* | ||
* Note: | ||
* | ||
* 1 <= A.length <= 10000 | ||
* 0 <= A[i] <= 9 | ||
* 0 <= K <= 10000 | ||
* If A.length > 1, then A[0] != 0 | ||
* | ||
******************************************************************************************************/ | ||
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class Solution { | ||
public: | ||
vector<int> addToArrayForm(vector<int>& A, int K) { | ||
int carry = K; | ||
for (int i = A.size() - 1; i >= 0 && carry > 0; i--) { | ||
int a = A[i] + carry; | ||
A[i] = a % 10 ; | ||
carry = a / 10; | ||
} | ||
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while ( carry > 0 ) { | ||
A.insert(A.begin(), carry%10); | ||
carry /= 10; | ||
} | ||
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return A; | ||
} | ||
}; |