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102.二叉树的层次遍历.java
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102.二叉树的层次遍历.java
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/*
* @lc app=leetcode.cn id=102 lang=java
*
* [102] 二叉树的层次遍历
*
* https://leetcode-cn.com/problems/binary-tree-level-order-traversal/description/
*
* algorithms
* Medium (57.77%)
* Likes: 261
* Dislikes: 0
* Total Accepted: 42.2K
* Total Submissions: 72.1K
* Testcase Example: '[3,9,20,null,null,15,7]'
*
* 给定一个二叉树,返回其按层次遍历的节点值。 (即逐层地,从左到右访问所有节点)。
*
* 例如:
* 给定二叉树: [3,9,20,null,null,15,7],
*
* 3
* / \
* 9 20
* / \
* 15 7
*
*
* 返回其层次遍历结果:
*
* [
* [3],
* [9,20],
* [15,7]
* ]
*
*
*/
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<List<Integer>> levelOrder(TreeNode root) {
List<List<Integer>> res = new ArrayList<>();
Queue<TreeNode> queue = new LinkedList<>();
queue.add(root);
while (!queue.isEmpty()) {
int size = queue.size();
List<Integer> list = new ArrayList<>();
for (int i = 0; i < size; i++) {
TreeNode node = queue.poll();
if (node != null) {
list.add(node.val);
queue.add(node.left);
queue.add(node.right);
}
}
if (!list.isEmpty()) {
res.add(list);
}
}
return res;
}
}