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1002.查找常用字符.java
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1002.查找常用字符.java
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/*
* @lc app=leetcode.cn id=1002 lang=java
*
* [1002] 查找常用字符
*
* https://leetcode-cn.com/problems/find-common-characters/description/
*
* algorithms
* Easy (68.84%)
* Likes: 141
* Dislikes: 0
* Total Accepted: 27.6K
* Total Submissions: 37.8K
* Testcase Example: '["bella","label","roller"]'
*
* 给定仅有小写字母组成的字符串数组 A,返回列表中的每个字符串中都显示的全部字符(包括重复字符)组成的列表。例如,如果一个字符在每个字符串中出现 3
* 次,但不是 4 次,则需要在最终答案中包含该字符 3 次。
*
* 你可以按任意顺序返回答案。
*
*
*
* 示例 1:
*
* 输入:["bella","label","roller"]
* 输出:["e","l","l"]
*
*
* 示例 2:
*
* 输入:["cool","lock","cook"]
* 输出:["c","o"]
*
*
*
*
* 提示:
*
*
* 1 <= A.length <= 100
* 1 <= A[i].length <= 100
* A[i][j] 是小写字母
*
*
*/
// @lc code=start
class Solution {
public List<String> commonChars(String[] A) {
List<String> ans = new ArrayList<>();
int[] count = new int[26];
Arrays.fill(count, 100);
for (String s : A) {
int[] tmp = new int[26];
for (char c : s.toCharArray()) {
tmp[c - 'a']++;
}
for (int i = 0; i < 26; i++) {
if (tmp[i] < count[i]) {
count[i] = tmp[i];
}
}
}
for (int i = 0; i < 26; i++) {
for (int x = 0; x < count[i]; x++) {
ans.add(String.valueOf((char) (i + 'a')));
}
}
return ans;
}
}
// @lc code=end