code_highlight.Rmd

---
title: "Code Hightlight"
author: "etibhar"
date: "4 October 2016"
output: 
  html_document:
    highlight: pygments
---

```{r,echo=FALSE}
library(rmarkdown)
```

## Bash

```{r, engine='bash'}
#!/bin/bash
# bash trap command
trap bashtrap INT
# bash clear screen command
clear;
# bash trap function is executed when CTRL-C is pressed:
# bash prints message => Executing bash trap subrutine !
bashtrap()
{
    echo "CTRL+C Detected !...executing bash trap !"
}
# for loop from 1/10 to 10/10
for a in `seq 1 10`; do
    echo "$a/10 to Exit." 
    #sleep 1;
done
echo "Exit Bash Trap Example!!!" 
```

## Basic

```{r, engine='basic', eval=F}
Declare Sub PrintArray()

Dim Numbers(1 To 10) As Integer
Dim Shared OtherNumbers(1 To 10) As Integer
Dim a As Integer

Numbers(1) = 1
Numbers(2) = 2
OtherNumbers(1) = 3
OtherNumbers(2) = 4

PrintArray ()

For a = 1 To 10
 Print Numbers(a)
Next a

Sub PrintArray ()
 Dim a As Integer
 For a = 1 To 10
   Print otherNumbers(a)
 Next a
End Sub
```

## C

```{r, engine='c'}
#include <stdio.h>

int main()
{
    int year;

    printf("Enter a year: ");
    scanf("%d",&year);

    if(year%4 == 0)
    {
        if( year%100 == 0)
        {
            // year is divisible by 400, hence the year is a leap year
            if ( year%400 == 0)
                printf("%d is a leap year.", year);
            else
                printf("%d is not a leap year.", year);
        }
        else
            printf("%d is a leap year.", year );
    }
    else
        printf("%d is not a leap year.", year);
    
    return 0;
}
```

## Java

```{r, engine='java', eval=F}
/*
  Even Odd Number Example
  This Java Even Odd Number Example shows how to check if the given
  number is even or odd.
*/
 
public class FindEvenOrOddNumber {
 
        public static void main(String[] args) {
               
                //create an array of 10 numbers
                int[] numbers = new int[]{1,2,3,4,5,6,7,8,9,10};
               
                for(int i=0; i < numbers.length; i++){
                       
                        /*
                         * use modulus operator to check if the number is even or odd. 
                         * If we divide any number by 2 and reminder is 0 then the number is
                         * even, otherwise it is odd.
                         */
                         
                         if(numbers[i]%2 == 0)
                                System.out.println(numbers[i] + " is even number.");
                         else
                                System.out.println(numbers[i] + " is odd number.");
                               
                }
               
        }
}
```

## Perl

```{r, engine='perl'}
#!/usr/bin/perl
use strict;
use warnings;

use Spreadsheet::Read;

my $workbook = ReadData ("test.xls");
print $workbook->[1]{A3} . "\n";
```

## Python

```{r, engine='python'}
import re
for test_string in ['555-1212', 'ILL-EGAL']:
    if re.match(r'^\d{3}-\d{4}$', test_string):
        print test_string, 'is a valid US local phone number'
    else:
        print test_string, 'rejected'
```