-
Notifications
You must be signed in to change notification settings - Fork 1
/
introduction.py
291 lines (229 loc) · 7.6 KB
/
introduction.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
268
269
270
271
272
273
274
275
276
277
278
279
280
281
282
283
284
285
286
287
288
289
290
291
"""
Introduction / Finding Key Connectors
... In particular, he wants you to identify who the "key connectors" are among data scientists.
To this end, he gives you a dump of the entire DataSciencester network.
(In real life, people don't typically hand you thje data you need. Chapter 9 is devoted to getting data.)
What does this data dump look like? It consists of a list of users,each represented by a
`dict` that contains that user's `id` (which is a number) and `name` (which, in one of the great cosmic
coincidences, rhymes with the user's `id`):
"""
import collections
from typing import Dict, Union
users = [
{"id": 0, "name": "Hero"},
{"id": 1, "name": "Dunn"},
{"id": 2, "name": "Sue"},
{"id": 3, "name": "Chi"},
{"id": 4, "name": "Thor"},
{"id": 5, "name": "Clive"},
{"id": 6, "name": "Hicks"},
{"id": 7, "name": "Devin"},
{"id": 8, "name": "Kate"},
{"id": 9, "name": "Klein"},
]
friendship_pairs = [
(0, 1),
(0, 2),
(1, 2),
(1, 3),
(2, 3),
(3, 4),
(4, 5),
(5, 6),
(5, 7),
(6, 8),
(7, 8),
(8, 9),
]
# Initialize the dict with an empty list for each user id:
friendships = collections.defaultdict(list)
for left, right in friendship_pairs:
friendships[left].append(right)
friendships[right].append(left)
def number_of_friends(user: Dict[str, Union[int, str]]):
"""How many friends does _user_ have?"""
user_id = user["id"]
friend_ids = friendships[user_id]
return len(friend_ids)
total_connections = sum(number_of_friends(user) for user in users)
num_users = len(users)
avg_connections = total_connections / num_users
# Create a list (user_id, number_of_friends)
num_friends_by_id = [(user["id"], number_of_friends(user)) for user in users]
num_friends_by_id.sort(
key=lambda id_and_friends: id_and_friends[1],
reverse=True,
)
# Ranking users by their number of friends, most to least.
print(num_friends_by_id)
# Data Scientists You May Know
##############################
def foaf_ids_bad(user):
"""foaf is short for 'friend of a friend'."""
return [
foaf_id
for friend_id in friendships[user["id"]]
for foaf_id in friendships[friend_id]
]
assert foaf_ids_bad(users[0]) == [0, 2, 3, 0, 1, 3]
def friends_of_friends(user):
user_id = user["id"]
return collections.Counter(
foaf_id
for friend_id in friendships[user["id"]] # For each of my freinds
for foaf_id in friendships[friend_id] # find their friends
if foaf_id != user_id # who aren't me
and foaf_id not in friendships[user_id] # and aren't my friends
)
print(friends_of_friends(users[3]))
assert friends_of_friends(users[3]) == collections.Counter({0: 2, 5: 1})
"""
As a data scientist, you know that you also might enjoy meeting users with similar interests.
(This is a good examples of the "substantive expertise" aspect of data science.) After asking
around, you manage to get your hands on this data, as a list of pairs (user_id, interest):
"""
interests = [
(0, "Hadoop"),
(0, "Big Data"),
(0, "HBase"),
(0, "Java"),
(0, "Spark"),
(0, "Storm"),
(0, "Cassandra"),
(1, "NoSQL"),
(1, "MongoDB"),
(1, "Cassandra"),
(1, "HBase"),
(1, "Postgres"),
(2, "Python"),
(2, "scikit-learn"),
(2, "scipy"),
(2, "numpy"),
(2, "statsmodels"),
(2, "pandas"),
(3, "R"),
(3, "Python"),
(3, "statistics"),
(3, "regression"),
(3, "probability"),
(4, "machine learning"),
(4, "regression"),
(4, "decision trees"),
(4, "libsvm"),
(5, "Python"),
(5, "R"),
(5, "Java"),
(5, "C++"),
(5, "Haskell"),
(5, "programming languages"),
(6, "statistics"),
(6, "probability"),
(6, "mathematics"),
(6, "theory"),
(7, "machine learning"),
(7, "scikit-learn"),
(7, "Mahout"),
(7, "neural networks"),
(8, "neural networks"),
(8, "deep learning"),
(8, "Big Data"),
(8, "artificial intelligence"),
(9, "Hadoop"),
(9, "Java"),
(9, "MapReduce"),
(9, "Big Data"),
]
# Works but recomputes on every call.
def data_scientists_who_list(target_interest: str):
"""Find the ids of all users who like the target interest."""
return [user_id for user_id, interest in interests if interest == target_interest]
user_ids_by_interest = collections.defaultdict(list)
for user_id, interest_ in interests:
user_ids_by_interest[interest_].append(user_id)
interests_by_user_id = collections.defaultdict(list)
for user_id, interest_ in interests:
interests_by_user_id[user_id].append(interest_)
# Now it's easy to find who has the most interests in common with a given user
def most_common_interests_with(user):
return collections.Counter(
interested_user_id
for interest in interests_by_user_id[user["id"]]
for interested_user_id in user_ids_by_interest[interest]
if interested_user_id != user["id"]
)
# Salaries and Experience
##############################
"""
Right as you're about to head to lunch, the VP of Public Relations asks if you can provide
some fun facts about how much data scientists earn. Salary data is of course sensitive,
but he manages to provide you an anonymous dataset containing each user's `salary` (in dollars)
and `tenure` as a data scientist (in years).
"""
salaries_and_tenures = [
(83000, 8.7),
(88000, 8.1),
(48000, 0.7),
(76000, 6),
(69000, 6.5),
(76000, 7.5),
(60000, 2.5),
(83000, 10),
(48000, 1.9),
(63000, 4.2),
]
salary_by_tenure = collections.defaultdict(list)
for salary, tenure in salaries_and_tenures:
salary_by_tenure[tenure].append(salary)
# Keys are years, each value is average salary for that tenure
average_salary_by_tenure = {
tenure: sum(salaries) / len(salaries)
for tenure, salaries in salary_by_tenure.items()
}
print(f"Not particularly useful: {average_salary_by_tenure}")
def tenure_bucket(tenure):
if tenure < 2:
return "less than two"
elif tenure < 5:
return "between two and five"
else:
return "more than five"
# Keys are tenure buckets, values are lists of salaries for that bucket.
salary_by_tenure_bucket = collections.defaultdict(list)
for salary, tenure in salaries_and_tenures:
bucket = tenure_bucket(tenure)
salary_by_tenure_bucket[bucket].append(salary)
average_salary_by_bucket = {
tenure_bucket: sum(salaries) / len(salaries)
for tenure_bucket, salaries in salary_by_tenure_bucket.items()
}
print("Ave salary by bucket:")
print(average_salary_by_bucket)
# Paid Accounts
##############################
"""
When you get back to your desk, the VP of Revenue is waiting for you. She wants to
better understand which users pay for accounts and which don't. (She knows their names,
but that's not particularly actionable information.
"""
def predict_paid_or_unpaid(years_experience):
if years_experience < 3.0:
return "paid"
elif years_experience < 8.5:
return "unpaid"
else:
return "paid"
# Topics of Interest
##############################
"""
As you're wrapping up your first day, the VP of Content Strategy asks you for data about
what topics users are most interested in, so that she can plan out her blog calendar accordingly.
You already have the raw data from the friend-suggester project.
One simple (if not particularly exciting) way to find the most popular interest is to count the words.
"""
words_and_counts = collections.Counter(
word for user, interest in interests for word in interest.lower().split()
)
print("\nPOPULAR TOPICS:")
for word, count in words_and_counts.most_common():
if count > 1:
print(word, count)