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logic.py
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logic.py
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#
# CS1010FC --- Programming Methodology
#
# Mission N Solutions
#
# Note that written answers are commented out to allow us to run your
# code easily while grading your problem set.
from random import *
#######
#Task 1a#
#######
# [Marking Scheme]
# Points to note:
# Matrix elements must be equal but not identical
# 1 mark for creating the correct matrix
def new_game(n):
matrix = []
for i in range(n):
matrix.append([0] * n)
return matrix
###########
# Task 1b #
###########
# [Marking Scheme]
# Points to note:
# Must ensure that it is created on a zero entry
# 1 mark for creating the correct loop
def add_two(mat):
a=randint(0,len(mat)-1)
b=randint(0,len(mat)-1)
while(mat[a][b]!=0):
a=randint(0,len(mat)-1)
b=randint(0,len(mat)-1)
mat[a][b]=2
return mat
###########
# Task 1c #
###########
# [Marking Scheme]
# Points to note:
# Matrix elements must be equal but not identical
# 0 marks for completely wrong solutions
# 1 mark for getting only one condition correct
# 2 marks for getting two of the three conditions
# 3 marks for correct checking
def game_state(mat):
for i in range(len(mat)):
for j in range(len(mat[0])):
if mat[i][j]==2048:
return 'win'
for i in range(len(mat)-1): #intentionally reduced to check the row on the right and below
for j in range(len(mat[0])-1): #more elegant to use exceptions but most likely this will be their solution
if mat[i][j]==mat[i+1][j] or mat[i][j+1]==mat[i][j]:
return 'not over'
for i in range(len(mat)): #check for any zero entries
for j in range(len(mat[0])):
if mat[i][j]==0:
return 'not over'
for k in range(len(mat)-1): #to check the left/right entries on the last row
if mat[len(mat)-1][k]==mat[len(mat)-1][k+1]:
return 'not over'
for j in range(len(mat)-1): #check up/down entries on last column
if mat[j][len(mat)-1]==mat[j+1][len(mat)-1]:
return 'not over'
return 'lose'
###########
# Task 2a #
###########
# [Marking Scheme]
# Points to note:
# 0 marks for completely incorrect solutions
# 1 mark for solutions that show general understanding
# 2 marks for correct solutions that work for all sizes of matrices
def reverse(mat):
new=[]
for i in range(len(mat)):
new.append([])
for j in range(len(mat[0])):
new[i].append(mat[i][len(mat[0])-j-1])
return new
###########
# Task 2b #
###########
# [Marking Scheme]
# Points to note:
# 0 marks for completely incorrect solutions
# 1 mark for solutions that show general understanding
# 2 marks for correct solutions that work for all sizes of matrices
def transpose(mat):
new=[]
for i in range(len(mat[0])):
new.append([])
for j in range(len(mat)):
new[i].append(mat[j][i])
return new
##########
# Task 3 #
##########
# [Marking Scheme]
# Points to note:
# The way to do movement is compress -> merge -> compress again
# Basically if they can solve one side, and use transpose and reverse correctly they should
# be able to solve the entire thing just by flipping the matrix around
# No idea how to grade this one at the moment. I have it pegged to 8 (which gives you like,
# 2 per up/down/left/right?) But if you get one correct likely to get all correct so...
# Check the down one. Reverse/transpose if ordered wrongly will give you wrong result.
def cover_up(mat):
new=[[0,0,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,0]]
done=False
for i in range(4):
count=0
for j in range(4):
if mat[i][j]!=0:
new[i][count]=mat[i][j]
if j!=count:
done=True
count+=1
return (new,done)
def merge(mat):
done=False
for i in range(4):
for j in range(3):
if mat[i][j]==mat[i][j+1] and mat[i][j]!=0:
mat[i][j]*=2
mat[i][j+1]=0
done=True
return (mat,done)
def up(game):
print("up")
# return matrix after shifting up
game=transpose(game)
game,done=cover_up(game)
temp=merge(game)
game=temp[0]
done=done or temp[1]
game=cover_up(game)[0]
game=transpose(game)
return (game,done)
def down(game):
print("down")
game=reverse(transpose(game))
game,done=cover_up(game)
temp=merge(game)
game=temp[0]
done=done or temp[1]
game=cover_up(game)[0]
game=transpose(reverse(game))
return (game,done)
def left(game):
print("left")
# return matrix after shifting left
game,done=cover_up(game)
temp=merge(game)
game=temp[0]
done=done or temp[1]
game=cover_up(game)[0]
return (game,done)
def right(game):
print("right")
# return matrix after shifting right
game=reverse(game)
game,done=cover_up(game)
temp=merge(game)
game=temp[0]
done=done or temp[1]
game=cover_up(game)[0]
game=reverse(game)
return (game,done)