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ParseResult and its subtype are members of scala.util.parsing.combinator.Parsers #236

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jm-g opened this issue Aug 19, 2019 · 1 comment
Open

ParseResult and its subtype are members of scala.util.parsing.combinator.Parsers #236

jm-g opened this issue Aug 19, 2019 · 1 comment

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@jm-g
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jm-g commented Aug 19, 2019

ParseResult and its subtype are members of scala.util.parsing.combinator.Parsers. Why? This limits the ability to write code using ParseResult without any added benefit as far as I can see.

E.g. I would like to define a scalatest Matcher. I have to wrap it now into a scope, parameterized by a Parsers instance or I have to redefine the Matcher in every test case.
@SethTisue
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it wouldn't surprise me if it's for no reason

@peteraldous peteraldous mentioned this issue May 11, 2022
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@SethTisue @jm-g