-
Notifications
You must be signed in to change notification settings - Fork 1
/
LibraryFine.py
95 lines (66 loc) · 2.67 KB
/
LibraryFine.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
"""
Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:
If the book is returned on or before the expected return date, no fine will be charged (i.e.: .
If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, .
If the book is returned after the expected return month but still within the same calendar year as the expected return date, the .
If the book is returned after the calendar year in which it was expected, there is a fixed fine of .
Charges are based only on the least precise measure of lateness. For example, whether a book is due January 1, 2017 or December 31, 2017, if it is returned January 1, 2018, that is a year late and the fine would be .
Function Description
Complete the libraryFine function in the editor below. It must return an integer representing the fine due.
libraryFine has the following parameter(s):
d1, m1, y1: returned date day, month and year
d2, m2, y2: due date day, month and year
Input Format
The first line contains space-separated integers, , denoting the respective , , and on which the book was returned.
The second line contains space-separated integers, , denoting the respective , , and on which the book was due to be returned.
Constraints
Output Format
Print a single integer denoting the library fine for the book received as input.
Sample Input
9 6 2015
6 6 2015
Sample Output
45
Explanation
Given the following dates:
Returned:
Due:
Because , we know it is less than a year late.
Because , we know it's less than a month late.
Because , we know that it was returned late (but still within the same month and year).
Per the library's fee structure, we know that our fine will be . We then print the result of as our output.
"""
# SOLUTION
#!/bin/python3
import math
import os
import random
import re
import sys
# Complete the libraryFine function below.
def libraryFine(d1, m1, y1, d2, m2, y2):
fine = 0
if y1 > y2 :
fine = 10000
if y1 == y2 :
if m1 > m2 :
fine = (m1-m2)*500
if m1 == m2 :
if d1 > d2 :
fine = (d1-d2)*15
else:
fine = 0
return fine
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
d1M1Y1 = input().split()
d1 = int(d1M1Y1[0])
m1 = int(d1M1Y1[1])
y1 = int(d1M1Y1[2])
d2M2Y2 = input().split()
d2 = int(d2M2Y2[0])
m2 = int(d2M2Y2[1])
y2 = int(d2M2Y2[2])
result = libraryFine(d1, m1, y1, d2, m2, y2)
fptr.write(str(result) + '\n')
fptr.close()