access to Glacier2 router in python

[FrankRulof]

Hello,

I am writing a client for the mumble server and using Glacier2 and ICE as interfaces. I =created the following python code from a C++ piece of code the code is as follows
import Ice
import Glacier2
import sys
import MumbleServer # Your generated MumbleServer module

Initialize the Ice communicator

initData = Ice.InitializationData()
initData.properties = Ice.createProperties()
initData.properties.setProperty('Ice.Default.Router', 'DemoGlacier2Router/router:default -p 4063 -h 192.168.1.63')
#initData.properties.setProperty('Ice.Default.Router', 'Glacier2/router:default -p 4063 -h 192.168.1.63')
iceCommunicator = Ice.initialize(initData)
print ("1")

try:
# Get the default router from the communicator
#murmurRouter = Glacier2.RouterPrx.uncheckedCast(iceCommunicator.getDefaultRouter())
murmurRouter = Glacier2.RouterPrx.uncheckedCast(iceCommunicator.getDefaultRouter())
print ("2")

# Now you can use murmurRouter to create a session or perform other operations
# For example:
session = Glacier2.RouterPrx.createSession("SuperUser", "linuxtar")
print ("session="+session)

# Obtain a proxy for the Meta service
meta = MumbleServer.MetaPrx.uncheckedCast(murmurRouter.getSession().ice_router)
print ("meta="+meta)

when executing the code an error :: Error: RouterPrx.createSession() missing 1 required positional argument: 'password' I dont understand this error , the mumble server is running with the above user and password. The mumble client can connect. Can you help me with that ?
Thanks in advance

[pepone]

This is not correct:

session = Glacier2.RouterPrx.createSession("SuperUser", "linuxtar")

You must call createSession on the proxy you created before, something like:

session = murmurRouter.createSession("SuperUser", "linuxtar")

No clear what are you trying to do in the following code:

# Obtain a proxy for the Meta service
meta = MumbleServer.MetaPrx.uncheckedCast(murmurRouter.getSession().ice_router)
print ("meta="+meta)

You might want to take a look at the Python Glacier2 demo at https://github.com/zeroc-ice/ice-demos/blob/3.7/python/Glacier2/callback/client.py

[FrankRulof]

Thanks for your answer , i am going to look at the example you indicated
To aswer your remark "No clear what are you trying to do in the following code: "The intend of the python code is to create a client that can control the administration (channels , ACL , users) of the mumble server, so meta is the base to be able to do so and i thought it needs the session from the router. can you guide me in that respect ?

[FrankRulof]

when i change "session = Glacier2.RouterPrx.createSession("SuperUser", "linuxtar")" into "session = murmurRouter.createSession("SuperUser", "linuxtar")" i get the error
Error: exception ::Ice::ObjectNotExistException
{
id =
{
name = router
category = DemoGlacier2Router
}
facet =
operation = createSession
}
What does this error mean ? I hope you can help me

[pepone]

It means that the object with ID DemoGlacier2Router/router is not hosted by the target server.

A Glacier2 router hosts a well-known object whose identity is derived from the Glacier2.InstanceName configuration property. See https://doc.zeroc.com/ice/latest/ice-services/glacier2/getting-started-with-glacier2#id-.GettingStartedwithGlacier2v3.7-Glacier2ObjectIdentities

No clear what are you trying to do in the following code: "The intend of the python code is to create a client that can control the administration (channels , ACL , users) of the mumble serve

It would be better to ask this question in the Mumble forum.

I just asked because the code doesn't look correct

# Obtain a proxy for the Meta service
meta = MumbleServer.MetaPrx.uncheckedCast(murmurRouter.getSession().ice_router)
print ("meta="+meta)

Here murmurRouter seems to be a proxy of type Glacier2.RouterPrx which doesn't have a getSession operation.