Add support for translating instanceof

[SalehAly]

Hey

I have a super class which is extended by sub class, the super class has a Discriminator Column and each sub class has its own Discriminator value, Lets say that Animal is the super class , Cat is the sub class

now if I try this

 where(animal -> animal instanceof Cat) 

it throws an Exception

Exception in thread "main" java.lang.IllegalArgumentException: Could not analyze lambda code
org.jinq.rebased.org.objectweb.asm.tree.analysis.AnalyzerException: 
Unhandled bytecode instruction

Note that, we dont have an attribute that maps to the discriminator column, but even if we could add it and then JinQ was able pick it up and use it instead of instance of, it will still be a work around and not a perfect solution

is there any possible way to detect inheritance ?

I think since JPA 2.0, there is a TYPE command, and I think also it can detect the discriminator column.
http://stackoverflow.com/questions/7807608/how-to-create-an-instance-of-like-query-in-jpa-2-0

[my2iu]

Jinq does not support translating instanceof at the moment. Since you have a workaround (making an attribute for the discriminator column), it might be a while before I have the time to look at it.

I think JPA doesn't support casting from one type to another, so even if I were to add support for TYPE to Jinq, it would only be useful for a very small number of queries.

[SalehAly]

I implemented the work around and it did the job for now,
I will just rename the issue to Add Support For transalting instanceof

Thank you