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using PFFT is causing error, not sure why! #31
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okay, I need to update this thread here, because I found out something very interesting. check out what I did below: N = np.array([12, 20], dtype=int)
and then use fft, it works just fine!!
sorry for typing twice here |
Hi |
Hi Mikael, environment: packages being used installed via pip: I also tried to trace the error to the file fftw_xfftn.pyx line 152 Ahmad |
Hi,
I am following the example as in this thread just to make sure that everything works fine,
from mpi4py import MPI
from mpi4py_fft import PFFT, newDistArray
FFT = PFFT(MPI.COMM_WORLD, [64, 64, 64])
u = newDistArray(FFT, False, rank=1)
u_hat = newDistArray(FFT, True, rank=1)
but when I call PFFT(), the following error occurs,
PFFT(MPI.COMM_WORLD, [64, 64, 64])
Traceback (most recent call last):
File "", line 1, in
File "/home/ahmad68/.conda/envs/kmc/lib/python3.9/site-packages/mpi4py_fft/mpifft.py", line 315, in init
xfftn = FFT(pencil.subshape, axes, dtype, padding, backend=backend,
File "/home/ahmad68/.conda/envs/kmc/lib/python3.9/site-packages/mpi4py_fft/libfft.py", line 387, in init
self.fwd, self.bck = plan(self.shape, self.axes, self.dtype, transforms, kw)
File "/home/ahmad68/.conda/envs/kmc/lib/python3.9/site-packages/mpi4py_fft/libfft.py", line 73, in _Xfftn_plan_fftw
xfftn_fwd = plan_fwd(U, s=s, axes=axes, threads=threads, flags=flags)
File "/home/ahmad68/.conda/envs/kmc/lib/python3.9/site-packages/mpi4py_fft/fftw/xfftn.py", line 239, in rfftn
return get_planned_FFT(input_array, output_array, axes, kind, threads,
File "/home/ahmad68/.conda/envs/kmc/lib/python3.9/site-packages/mpi4py_fft/fftw/factory.py", line 106, in get_planned_FFT
return _fft.FFT(input_array, output_array, axes, kind, threads, flags,
File "mpi4py_fft/fftw/fftw_xfftn.pyx", line 153, in mpi4py_fft.fftw.fftw_xfftn.FFT.cinit
RuntimeError: Failure creating FFTW plan
thanks a lot,
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