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The Impossibility of Trisecting the Angle and Doubling the Cube (metamath 100 #8) #4246
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Maybe worth mentioning that the proof doesn't require a great deal of Galois theory, in fact the only crucial bit seems to be that field extensions are multiplicative, and that is already proved in set.mm in extdgmul. The fact that the cubic root of 2 gives us a field extension of degree 3 can be proved by elementary means, by mimicking the argument about minimal polynomials. Probably the most laborious part would be to define constructible numbers and prove that they give field extensions of degree a power of 2. I took a look at how other formalization systems do this, and both HOL Light and Isabelle go with the geometrical definition. That is, we start with two points (if we identify points on the plane with vectors, then usually
I think it would be beneficial to model constructible numbers in set.mm as a subset of complex numbers, as we do in section "Theorems of Pythagoras, isosceles triangles, and intersecting chords" of set.mm. Geometry of I unfortunately don't know how recursive definitions work in set.mm, so I cannot draft a preliminary definition of constructible (complex) numbers, but it seems that we should start with 0 and 1 as being constructible by default and properties 1)-3) can be easily stated with standard operations with complex numbers, for example, one can use something in the spirit of sigarcol to test if points lie on the same line. The next step would be to show that construcible numbers form a field (again, I think the fact that we would be able to use I would be glad to participate and discuss the details if someone is willing to try formalizing some of the definitions and intermediate steps required. |
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An elegant proof would certainly rely on Galois Theory.
Such a proof is provided Chapter 7.4 of [Ian Stweart - Galois Theory], p.99, theorems 7.13 and 7.14.
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