Error when trying to join telegram protocol link

[girlpunk]

Some telegram rooms are linked with the tg protocol handler, intended to be handled by the browser and open the Telegram app. For example: tg://resolve?domain=ABC.

When trying to join such a link using !tg join tg://resolve?domain=ABC, the following error occurs

Traceback (most recent call last):
  File "/usr/lib/python3.11/site-packages/mautrix/bridge/commands/handler.py", line 491, in handle
    await self._run_handler(handler, evt)
  File "/usr/lib/python3.11/site-packages/mautrix_telegram/commands/handler.py", line 194, in _run_handler
    return await handler(evt)
           ^^^^^^^^^^^^^^^^^^
  File "/usr/lib/python3.11/site-packages/mautrix/bridge/commands/handler.py", line 340, in __call__
    return await self._handler(evt)
           ^^^^^^^^^^^^^^^^^^^^^^^^
  File "/usr/lib/python3.11/site-packages/mautrix_telegram/commands/telegram/misc.py", line 271, in join
    async with ClientSession() as sess, sess.get(url) as resp:
  File "/usr/lib/python3.11/site-packages/aiohttp/client.py", line 1167, in __aenter__
    self._resp = await self._coro
                 ^^^^^^^^^^^^^^^^
  File "/usr/lib/python3.11/site-packages/aiohttp/client.py", line 562, in _request
    conn = await self._connector.connect(
           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/usr/lib/python3.11/site-packages/aiohttp/connector.py", line 540, in connect
    proto = await self._create_connection(req, traces, timeout)
            ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/usr/lib/python3.11/site-packages/aiohttp/connector.py", line 901, in _create_connection
    _, proto = await self._create_direct_connection(req, traces, timeout)
               ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "/usr/lib/python3.11/site-packages/aiohttp/connector.py", line 1147, in _create_direct_connection
    assert port is not None
           ^^^^^^^^^^^^^^^^
AssertionError

I believe these links are functionally identical, albeit in a different format. As such, the above example should be equivalent to https://t.me/ABC