Given an array of integers A, a move consists of choosing any A[i]
, and incrementing it by 1
.
Return the least number of moves to make every value in A
unique.
Example 1:
Input: [1,2,2] Output: 1 Explanation: After 1 move, the array could be [1, 2, 3].
Example 2:
Input: [3,2,1,2,1,7] Output: 6 Explanation: After 6 moves, the array could be [3, 4, 1, 2, 5, 7]. It can be shown with 5 or less moves that it is impossible for the array to have all unique values.
Note:
0 <= A.length <= 40000
0 <= A[i] < 40000
Related Topics:
Array
// OJ: https://leetcode.com/problems/minimum-increment-to-make-array-unique/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int minIncrementForUnique(vector<int>& A) {
sort(A.begin(), A.end());
int ans = 0;
for (int i = 1; i < A.size(); ++i) {
if (A[i] > A[i - 1]) continue;
ans += A[i - 1] + 1 - A[i];
A[i] = A[i - 1] + 1;
}
return ans;
}
};