Design a stack-like data structure to push elements to the stack and pop the most frequent element from the stack.
Implement the FreqStack
class:
FreqStack()
constructs an empty frequency stack.void push(int val)
pushes an integerval
onto the top of the stack.int pop()
removes and returns the most frequent element in the stack.- If there is a tie for the most frequent element, the element closest to the stack's top is removed and returned.
Example 1:
Input ["FreqStack", "push", "push", "push", "push", "push", "push", "pop", "pop", "pop", "pop"] [[], [5], [7], [5], [7], [4], [5], [], [], [], []] Output [null, null, null, null, null, null, null, 5, 7, 5, 4] Explanation FreqStack freqStack = new FreqStack(); freqStack.push(5); // The stack is [5] freqStack.push(7); // The stack is [5,7] freqStack.push(5); // The stack is [5,7,5] freqStack.push(7); // The stack is [5,7,5,7] freqStack.push(4); // The stack is [5,7,5,7,4] freqStack.push(5); // The stack is [5,7,5,7,4,5] freqStack.pop(); // return 5, as 5 is the most frequent. The stack becomes [5,7,5,7,4]. freqStack.pop(); // return 7, as 5 and 7 is the most frequent, but 7 is closest to the top. The stack becomes [5,7,5,4]. freqStack.pop(); // return 5, as 5 is the most frequent. The stack becomes [5,7,4]. freqStack.pop(); // return 4, as 4, 5 and 7 is the most frequent, but 4 is closest to the top. The stack becomes [5,7].
Constraints:
0 <= val <= 109
- At most
2 * 104
calls will be made topush
andpop
. - It is guaranteed that there will be at least one element in the stack before calling
pop
.
Related Topics:
Hash Table, Stack
We push elements based on frequency first then the order they pushed into the stack.
Consider input 5 7 5 7 4 5
, if we label their frequency at the top
1 1 2 2 1 3
5 7 5 7 4 5
We can reorder them in this way
1: 5 7 4
2: 5 7
3: 5
When popping elements, we pop the 3rd stack first, then the 2nd, then the 1st.
// OJ: https://leetcode.com/problems/maximum-frequency-stack/
// Author: github.com/lzl124631x
// Time: O(1) for all
// Space: O(N)
class FreqStack {
unordered_map<int, int> freq; // number -> frequency
vector<vector<int>> v; // frequency -> stack of numbers
public:
FreqStack() {}
void push(int val) {
int f = freq[val]++;
if (v.size() <= f) v.emplace_back();
v[f].push_back(val);
}
int pop() {
int val = v.back().back();
v.back().pop_back();
--freq[val];
if (v.back().empty()) v.pop_back();
return val;
}
};