Given the root
of a binary search tree and the lowest and highest boundaries as low
and high
, trim the tree so that all its elements lies in [low, high]
. Trimming the tree should not change the relative structure of the elements that will remain in the tree (i.e., any node's descendant should remain a descendant). It can be proven that there is a unique answer.
Return the root of the trimmed binary search tree. Note that the root may change depending on the given bounds.
Example 1:
Input: root = [1,0,2], low = 1, high = 2 Output: [1,null,2]
Example 2:
Input: root = [3,0,4,null,2,null,null,1], low = 1, high = 3 Output: [3,2,null,1]
Constraints:
- The number of nodes in the tree in the range
[1, 104]
. 0 <= Node.val <= 104
- The value of each node in the tree is unique.
root
is guaranteed to be a valid binary search tree.0 <= low <= high <= 104
Companies:
Amazon, Microsoft, Facebook
Related Topics:
Tree, Depth-First Search, Binary Search Tree, Binary Tree
// OJ: https://leetcode.com/problems/trim-a-binary-search-tree/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(logN)
class Solution {
public:
TreeNode* trimBST(TreeNode* root, int L, int R) {
if (!root) return nullptr;
if (root->val < L) return trimBST(root->right, L, R);
if (root->val > R) return trimBST(root->left, L, R);
root->left = trimBST(root->left, L, R);
root->right = trimBST(root->right, L, R);
return root;
}
};