Design your implementation of the circular double-ended queue (deque).
Your implementation should support following operations:
MyCircularDeque(k)
: Constructor, set the size of the deque to be k.insertFront()
: Adds an item at the front of Deque. Return true if the operation is successful.insertLast()
: Adds an item at the rear of Deque. Return true if the operation is successful.deleteFront()
: Deletes an item from the front of Deque. Return true if the operation is successful.deleteLast()
: Deletes an item from the rear of Deque. Return true if the operation is successful.getFront()
: Gets the front item from the Deque. If the deque is empty, return -1.getRear()
: Gets the last item from Deque. If the deque is empty, return -1.isEmpty()
: Checks whether Deque is empty or not.isFull()
: Checks whether Deque is full or not.
Example:
MyCircularDeque circularDeque = new MycircularDeque(3); // set the size to be 3 circularDeque.insertLast(1); // return true circularDeque.insertLast(2); // return true circularDeque.insertFront(3); // return true circularDeque.insertFront(4); // return false, the queue is full circularDeque.getRear(); // return 2 circularDeque.isFull(); // return true circularDeque.deleteLast(); // return true circularDeque.insertFront(4); // return true circularDeque.getFront(); // return 4
Note:
- All values will be in the range of [0, 1000].
- The number of operations will be in the range of [1, 1000].
- Please do not use the built-in Deque library.
Similar Questions:
// OJ: https://leetcode.com/problems/design-circular-deque/
// Author: github.com/lzl124631x
// Time: O(1) for all
// Space: O(K)
class MyCircularDeque {
vector<int> q;
int begin = 0, end = 0, k, cnt = 0;
public:
MyCircularDeque(int k) : q(k), k(k) {}
bool insertFront(int value) {
if (cnt == k) return false;
begin = (begin - 1 + k) % k;
q[begin] = value;
++cnt;
return true;
}
bool insertLast(int value) {
if (cnt == k) return false;
q[end] = value;
end = (end + 1) % k;
++cnt;
return true;
}
bool deleteFront() {
if (cnt == 0) return false;
begin = (begin + 1) % k;
--cnt;
return true;
}
bool deleteLast() {
if (cnt == 0) return false;
end = (end - 1 + k) % k;
--cnt;
return true;
}
int getFront() {
if (cnt == 0) return -1;
return q[begin];
}
int getRear() {
if (cnt == 0) return -1;
return q[(end - 1 + k) % k];
}
bool isEmpty() {
return cnt == 0;
}
bool isFull() {
return cnt == k;
}
};