Description
Given three tables: salesperson
, company
, orders
.
Output all the names in the table salesperson
, who didn’t have sales to company 'RED'.
Example
Input
Table: salesperson
+----------+------+--------+-----------------+-----------+ | sales_id | name | salary | commission_rate | hire_date | +----------+------+--------+-----------------+-----------+ | 1 | John | 100000 | 6 | 4/1/2006 | | 2 | Amy | 120000 | 5 | 5/1/2010 | | 3 | Mark | 65000 | 12 | 12/25/2008| | 4 | Pam | 25000 | 25 | 1/1/2005 | | 5 | Alex | 50000 | 10 | 2/3/2007 | +----------+------+--------+-----------------+-----------+The table
salesperson
holds the salesperson information. Every salesperson has a sales_id and a name.
Table: company
+---------+--------+------------+ | com_id | name | city | +---------+--------+------------+ | 1 | RED | Boston | | 2 | ORANGE | New York | | 3 | YELLOW | Boston | | 4 | GREEN | Austin | +---------+--------+------------+The table
company
holds the company information. Every company has a com_id and a name.
Table: orders
+----------+----------+---------+----------+--------+ | order_id | date | com_id | sales_id | amount | +----------+----------+---------+----------+--------+ | 1 | 1/1/2014 | 3 | 4 | 100000 | | 2 | 2/1/2014 | 4 | 5 | 5000 | | 3 | 3/1/2014 | 1 | 1 | 50000 | | 4 | 4/1/2014 | 1 | 4 | 25000 | +----------+----------+---------+----------+--------+The table
orders
holds the sales record information, salesperson and customer company are represented by sales_id and com_id.output
+------+ | name | +------+ | Amy | | Mark | | Alex | +------+
Explanation
According to order '3' and '4' in table orders
, it is easy to tell only salesperson 'John' and 'Alex' have sales to company 'RED',
so we need to output all the other names in table salesperson
.
# OJ: https://leetcode.com/problems/sales-person/
# Author: github.com/lzl124631x
SELECT
s.name
FROM
salesperson s
WHERE
s.sales_id NOT IN (
SELECT
o.sales_id
FROM
orders o
LEFT JOIN
company c ON o.com_id = c.com_id
WHERE
c.name = 'RED'
)