Given the root
of a binary tree, return the length of the diameter of the tree.
The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root
.
The length of a path between two nodes is represented by the number of edges between them.
Example 1:
Input: root = [1,2,3,4,5] Output: 3 Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3].
Example 2:
Input: root = [1,2] Output: 1
Constraints:
- The number of nodes in the tree is in the range
[1, 104]
. -100 <= Node.val <= 100
Companies:
Facebook, Amazon, Google, Microsoft, Bloomberg, Apple, Adobe, Tesla, Intuit
Related Topics:
Tree, Depth-First Search, Binary Tree
Similar Questions:
// OJ: https://leetcode.com/problems/diameter-of-binary-tree/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(H)
class Solution {
int ans = 0;
int postorder(TreeNode *root) {
if (!root) return 0;
int left = postorder(root->left), right = postorder(root->right);
ans = max(ans, left + right);
return 1 + max(left, right);
}
public:
int diameterOfBinaryTree(TreeNode* root) {
postorder(root);
return ans;
}
};