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You are given two integers, n and k.

An array of distinct positive integers is called a k-avoiding array if there does not exist any pair of distinct elements that sum to k.

Return the minimum possible sum of a k-avoiding array of length n.

 

Example 1:

Input: n = 5, k = 4
Output: 18
Explanation: Consider the k-avoiding array [1,2,4,5,6], which has a sum of 18.
It can be proven that there is no k-avoiding array with a sum less than 18.

Example 2:

Input: n = 2, k = 6
Output: 3
Explanation: We can construct the array [1,2], which has a sum of 3.
It can be proven that there is no k-avoiding array with a sum less than 3.

 

Constraints:

  • 1 <= n, k <= 50

Companies: Infosys

Related Topics:
Math, Greedy

Solution 1.

// OJ: https://leetcode.com/problems/determine-the-minimum-sum-of-a-k-avoiding-array
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(N)
class Solution {
public:
    int minimumSum(int n, int k) {
        int ans = 0;
        unordered_set<int> s;
        for (int i = 1; s.size() < n; ++i) {
            if (s.count(k - i)) continue;
            ans += i;
            s.insert(i);
        }
        return ans;
    }
};