Given an array of citations sorted in ascending order (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.
According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."
Example:
Input:citations = [0,1,3,5,6]
Output: 3 Explanation:[0,1,3,5,6]
means the researcher has5
papers in total and each of them had received 0, 1, 3, 5, 6
citations respectively. Since the researcher has3
papers with at least3
citations each and the remaining two with no more than3
citations each, her h-index is3
.
Note:
If there are several possible values for h, the maximum one is taken as the h-index.
Follow up:
- This is a follow up problem to H-Index, where
citations
is now guaranteed to be sorted in ascending order. - Could you solve it in logarithmic time complexity?
Related Topics:
Binary Search
Similar Questions:
// OJ: https://leetcode.com/problems/h-index-ii/
// Author: github.com/lzl124631x
// Time: O(logN)
// Space: O(1)
class Solution {
public:
int hIndex(vector<int>& A) {
int N = A.size(), L = 0, R = N - 1;
while (L <= R) {
int M = (L + R) / 2;
if (A[M] >= N - M) R = M - 1;
else L = M + 1;
}
return N - L;
}
};