Given an integer array nums
, return the number of subarrays filled with 0
.
A subarray is a contiguous non-empty sequence of elements within an array.
Example 1:
Input: nums = [1,3,0,0,2,0,0,4] Output: 6 Explanation: There are 4 occurrences of [0] as a subarray. There are 2 occurrences of [0,0] as a subarray. There is no occurrence of a subarray with a size more than 2 filled with 0. Therefore, we return 6.
Example 2:
Input: nums = [0,0,0,2,0,0] Output: 9 Explanation: There are 5 occurrences of [0] as a subarray. There are 3 occurrences of [0,0] as a subarray. There is 1 occurrence of [0,0,0] as a subarray. There is no occurrence of a subarray with a size more than 3 filled with 0. Therefore, we return 9.
Example 3:
Input: nums = [2,10,2019] Output: 0 Explanation: There is no subarray filled with 0. Therefore, we return 0.
Constraints:
1 <= nums.length <= 105
-109 <= nums[i] <= 109
Companies: Google
Similar Questions:
- Arithmetic Slices (Medium)
- Number of Smooth Descent Periods of a Stock (Medium)
- Length of the Longest Alphabetical Continuous Substring (Medium)
- Find Consecutive Integers from a Data Stream (Medium)
// OJ: https://leetcode.com/problems/number-of-zero-filled-subarrays
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
long long zeroFilledSubarray(vector<int>& A) {
long long ans = 0, N = A.size();
for (int i = 0; i < N; ++i) {
if (A[i] != 0) continue;
long long cnt = 1;
while (i + 1 < N && A[i + 1] == 0) ++i, ++cnt;
ans += cnt * (1 + cnt) / 2;
}
return ans;
}
};